Area of a Segment of a Circle, when only the radius is known.

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Homework Help Overview

The discussion revolves around finding the area of a segment of a circle when only the radius is known. The original poster presents a scenario involving a circle with a radius of 2 and points on its circumference, seeking assistance in determining the area bounded by a line segment and an arc.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore how to approach the problem without knowing the angle, with some discussing the formula for the area of a segment when the angle is known. Questions arise about determining the angle and the lengths of triangle sides involved.

Discussion Status

There is ongoing exploration of the relationships within the triangle formed by the points on the circle. Some participants provide guidance on how to find the angle and lengths, while others express uncertainty about the implications of the bisector and the triangle's properties.

Contextual Notes

Participants note that the bisector of a line segment and the properties of the triangle formed by the radius are crucial to solving the problem. There is a focus on understanding the geometry involved without reaching a definitive conclusion.

malam1990
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A circle has Centre 0 and radius 2. A, B and C are points on the circumference of a circle such that AB is the perpindicular bisector of 0C.

Find the area of the segment of the circle bounded by the line segment AB and the minor arc ACB.

Give the area in exact forms in terms of surds and pi.

I have uploaded the circle diagram as well.

I understand how to find the area of a segment of a circle when I know the angle and radius, but am unsure when I only know the radius. Any help will be greatly appreciated!

Cheers
 

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Well show me how you would do it if you knew the angle
 
I would use the formula:

A = \Pir2\theta/360 - 0.5r2sin\theta



cheers
 
hi malam1990! :smile:

(have a theta: θ :wink:)
malam1990 said:
A circle has Centre 0 and radius 2. A, B and C are points on the circumference of a circle such that AB is the perpindicular bisector of 0C.

I understand how to find the area of a segment of a circle when I know the angle and radius, but am unsure when I only know the radius.

but you do know the angle …

you know the lengths of two sides of triangle AOD (where D bisects AB) :wink:
 
OC, OA, and OB are all radii of the circle, right?
 
tiny-tim said:
hi malam1990! :smile:

(have a theta: θ :wink:)


but you do know the angle …

you know the lengths of two sides of triangle AOD (where D bisects AB) :wink:


Hi, thanks for the help, but I'm still not sure how I get to know the angle, the answer is probably really obvious but unfortunately I am just not seeing it. So far I have θ as 90 degress but am unsure whether this is correct.

Cheers for the help again! it is much appreciated!
 
SammyS said:
OC, OA, and OB are all radii of the circle, right?

yes they are.

cheers for any help.
 
hi malam1990! :smile:
tiny-tim said:
you know the lengths of two sides of triangle AOD (where D bisects AB) :wink:
malam1990 said:
Hi, thanks for the help, but I'm still not sure how I get to know the angle …

what are the lengths of two sides of triangle AOD ? :wink:
 
tiny-tim said:
hi malam1990! :smile:



what are the lengths of two sides of triangle AOD ? :wink:

well I know OA is 2 as it is the radius, but I am still unsure how I would get to know either OD or DA?

cheers
 
  • #10
but you know that D is the bisector of OC :wink:
 
  • #11
tiny-tim said:
but you know that D is the bisector of OC :wink:

I'm really sorry but I'm still not getting it, I can't see how it helps me know definitely the length of one of the other sides of the traingle AOD. :confused:
 
  • #12
SammyS said:
OC, OA, and OB are all radii of the circle, right?

Therefore, AB bisects OC.

That should let you find the angle!
 
  • #13
Would I be correct in thinking that OD would be 1 and AD being \sqrt{}3 ?

which would then give me 60deg for the angle AOD? and 120 deg for the angle of the whole sector AOB?
 
  • #14
yup! … AB bisects OC, so OD = OC/2 = 1, so the right-angled triangle has sides 2 1 and √3, and cosAOD = 1/2, so AOD = 60° :smile:
 
  • #15
tiny-tim said:
yup! … AB bisects OC, so OD = OC/2 = 1, so the right-angled triangle has sides 2 1 and √3, and cosAOD = 1/2, so AOD = 60° :smile:

thank you so much for guiding me to finally seeing how to do it!

thanks again! you really have helped me out!
 

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