MHB Area of Triangle ABC: Find the Solution

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To find the area of triangle ABC with sides AC = 4 cm, AB = 3 cm, and angle A = 60 degrees, the formula A = 1/2 * a * b * sin(θ) is applicable. Substituting the values, the area can be calculated as A = 1/2 * 4 * 3 * sin(60°). The sine of 60 degrees is √3/2, leading to an area of 6√3/4 cm², which simplifies to approximately 2.598 cm². The height from point C can also be derived using the area formula, confirming the calculations.
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ABC is a triangle. AC=4cm; AB=3cm; A=60 degrees.
I need help finding the area of triangle ABC.
 
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Can you calculate the height from point C ?
 
If you know the lengths of two sides of a triangle (we'll call them \(a\) and \(b\)), and the angle \(\theta\) subtended by the two sides, then the area \(A\) of the triangle is given by:

$$A=\frac{1}{2}ab\sin(\theta)$$

Can you proceed?
 

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