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Area under force vs displacement graph :D?

  1. Apr 28, 2015 #1
    1. The problem statement, all variables and given/known data
    Find K at 4m, besides the F.s graph they also give me Kinitial = 2J

    2. Relevant equations
    W=F.d and W=Kf- Ki
    3. The attempt at a solution
    The first thing I did was to find the area under the graph.
    1/2(4)(2)=4J W=F.d so that's my work.
    Then I replaced that 4J into the other eq W= Kf-Ki
    then solved for Kf.
    W+Ki=Kf
    plugging in values 4j +(2J)=Kf
    then 6J=Kf
    Is that correct guys? Thanks for your help!
     

    Attached Files:

  2. jcsd
  3. Apr 28, 2015 #2

    PhanthomJay

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    looks good! Always put a space between the numerical value and the unit, 6 J not 6J.
     
  4. Apr 28, 2015 #3
    Thank you good sir! I will next time! :D good night!
     
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