Acceleration Vs. Displacement Graph

[manfriction]

I Have a question

If acceleration(a)=Displacement(x)
and at time(t)=0 if Velocity(u) is 0
then we have to find velocity at time=2 secs

Attempt At Answer
given: a=x
or v dv = x dx
integrating both sides with initial velocity 0 and displ. s
v2=x2-s2
or
v=√(x2-s2)
or
dx/√(x2-s2)=dt
integrating again
we get
(x/s)=cos t

but the problem is how do we get value of initial displ. s??
if we ignore s
we get
x=e^t
but the graph of this gives x=1 at t=o so we can't ignore "s"

Plz help..

 

[HallsofIvy]

"displacement" is the distance moved- not just the final position. Take initial s to be anything you like since you would just subtract it off anyway. s= 0 is easiest.