Argument Theorem - Complex Analysis

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The discussion centers on evaluating a contour integral using the Argument Theorem in complex analysis. The integral involves the function f(z) = (3z^n) - 1, which has n zeros, while the numerator z^(n-1) has (n-1) zeros. The initial calculation incorrectly considered the zeros of both the numerator and denominator, leading to an incorrect result of -1. The correct approach requires counting only the zeros of f(z) and acknowledging the derivative's contribution. The conclusion emphasizes the importance of correctly applying the Argument Principle and considering the contour's properties.
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Homework Statement



Evaluate (1/2ipi)* contour integral of [z^(n-1)] / [(3z^n) - 1 ] dz

Homework Equations



I would assume you would have to use the Argument Theorem since this problem comes after the proof of the argument theorem in my book.


The Attempt at a Solution



z^(n-1) has (n-1) zeros
(3z^n) - 1 has n zeros

therefore the integral is equal to (n-1)-n = -1

Is this correct?

Thanks
 
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Yes, use the Argument Principle, but no, you did it incorrectly.

If you are integrating f'(z)/f(z), then count the zeros (n) and poles (none) of f(z) only, not f'(z). Also, if f(z)=3z^n-1, then f'(z)=3nz^(n-1) so don't forget to take the 3n into account.

I guess you are assuming the contour is a simple closed contour enclosing all the roots of f(z).
 
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