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## Main Question or Discussion Point

Hey,

(sin A + sin B + sin C)/3 >= [tex]\sqrt[3]{}[/tex](sin A*sin B*sin C)

I know this is true by Arithmetic mean always greater than geometric mean...

but is there any other way of proving this?

(sin A + sin B + sin C)/3 >= [tex]\sqrt[3]{}[/tex](sin A*sin B*sin C)

I know this is true by Arithmetic mean always greater than geometric mean...

but is there any other way of proving this?