Inequality of arithmetic and geometric means

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Numeriprimi
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Hey! I have this: 2(√(1-a^2 ))+ 2a
How to determine the maximum value of this?

I think good for this is Inequality of arithmetic and geometric means, but I don't know how use this, because I don't calculate with this yet.

So, have you got any ideas?



Poor Czech Numeriprimi... If you don't understand my primitive English, write, I will try to write this better ;-)
 
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Carrying that farther [itex]f(a)= 2(1- a^2)^{1/2}+ 2a[/itex] has derivative [itex]f'(a)= -2(1- a^2)^{-1/2}+ 2[/itex]. Any maximum (or minimum) must occur where that derivative is 0 or does not exist. It does not exist when a= 1 or -1 because in that case we have a 0 in the denominator. It is 0 when [itex]\sqrt{1- a^2}= 1[/itex] or a= 0.

Check the values of [itex]2\sqrt{1- a^2}+ 2a[/itex] at x= -1, 0, and 1 to see which is the maximum value.

Another way to look at this is to see that if [itex]y= 2\sqrt{1- a^2}+ 2a[/itex] then [itex]y- 2a= 2\sqrt{1- a^2}[/itex] and so [itex]y^2- 4ay+ 4a^2= 4- 4a^2[/itex] or [itex]8a^2- 4ay+ y^2= 4[/itex] which is the graph of an ellipse with major and minor axes rotated from the coordinate axes.
 
Please, derivate no... I still have a few years time to learn this.
I need to use Inequality of arithmetic and geometric means, bud how?
 
Your expression has two parts, ##2\sqrt{1-a^2}## amd ##2a##.

If you are supposed to use arithmetic and geometric means, you need to find some quantities that give those arithmetic and geometric means.

For example if the quantities are ##x## and ##y## and the arithmetic mean is ##2a##, you have the equation ##(x+y)/2 = 2a##

And you have another equation for the geometric mean ...
 
Yes, i have this: n=4
And what now?