Arithmetic mean and standard deviation

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SUMMARY

The discussion focuses on calculating the arithmetic mean and standard deviation of days lost to sickness using frequency data. The user, Lloyd, correctly identifies the mid-points of the classes for days lost and applies the weighted mean formula to derive the arithmetic mean of 7.85. Additionally, Lloyd calculates the variance as 16.1775 and the standard deviation as approximately 4.02. The conversation highlights the importance of adhering to specific terminology, such as "mid-points of the classes" and "weighted means," for academic success.

PREREQUISITES
  • Understanding of basic statistics concepts, including mean and standard deviation
  • Familiarity with frequency distribution and class intervals
  • Knowledge of weighted averages and their calculations
  • Ability to perform arithmetic operations and square root calculations
NEXT STEPS
  • Research "weighted means" to deepen understanding of mean calculations in frequency distributions
  • Study "variance and standard deviation calculations" for comprehensive statistical analysis
  • Explore "frequency distribution tables" to enhance data representation skills
  • Review "mid-points of class intervals" for accurate statistical computations
USEFUL FOR

Students in statistics courses, data analysts, and anyone involved in quantitative research who needs to calculate and interpret mean and standard deviation from frequency data.

LDC1972
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Homework Statement



Showing all your working, calculate the arithmetic mean and standard deviation of the number of days lost.

Table shows man days lost to sickness..

Days lost: 1-3 4-6 7-9 10-12 13-15
Frequency 8 7 10 9 6

Homework Equations


n
They've given us this Ma = Ʃ = Xi / N
I=1

The Attempt at a Solution



The textbook they've supplied is really poor. They go into detail on all values centred around a single array. Obviously mine is a double...

So using Google and previous experience I've done this:

Taken medians of Days lost=

1-3 4-6 7-9 10-12 3-15
2 5 8 11 14 (medians)

median of frequency of days lost = 8 (central number as odd amount of numbers)

Multiplied median of days lost by frequency - (2x8) + (5x7) + (8x10) + 11x9) + (14x6) = 314

Summed frequency values 8 + 7 + 10 + 9 + 6 = 40 (Total frequency)

Divided 314/40 = 7.85 Arithmetic mean

Calculated variance
= median of days lost - Arithmetic mean

i.e 2 - 7.85 = 5.85 etc

Squared all results removing negative values to positive I.e -5.85^2 = 34.2225, did same for rest.

Multiplied squares by frequency i.e 34.2225 x 8 = 273.78 etc through the 5 values

Added all multiples 647.1

Divided multiples by 40 (the frequency) 64701/40 = 16.1775

Therefore σ2 = 16.1775 (The variance)

Calculated standard deviation by √16.1775 = 4.02212603

Basically if someone would be o kind as to confirm my approach and answers that'd be great But I don't expect anyone to spend hours on this!

Thanks for help if you can.

Lloyd
 
Last edited:
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What you refer to as "taking the medians" is referred to in this setting as "using the mid-points of the classes" (or other writer-dependent language). The calculations then proceed as you've done.
The calculation for finding the mean is actually a use of the idea of "weighted means" - you may have luck finding more information by searching for that term.
 
statdad said:
What you refer to as "taking the medians" is referred to in this setting as "using the mid-points of the classes" (or other writer-dependent language). The calculations then proceed as you've done.
The calculation for finding the mean is actually a use of the idea of "weighted means" - you may have luck finding more information by searching for that term.

Thank you for the really fast reply.

I've stuck with the university's terminology. For my last assignment I didn't get a single question wrong but only got a merit, not a distinction - probably because I didn't follow their nonsense.

Others I've painfully followed their way and got distinctions.

So I'm sticking as close as I can to their terminology but agree with you 100%.

Trouble I my tutor is only available Fridays and Mondays and I missed him today. This is the lat exam of this module before exit interview and I'm going to voice my concerns!

Having this forum for the rest of the time is invaluable.

Thank you!
 

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