Calculating potential on surface of sphere

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SUMMARY

The discussion centers on calculating the radius of a spherical drop of water with a charge of 30 pC and a potential of 500 V at its surface. The relevant equation used is Potential = (1/4πε) q/r. Participants confirmed that for this problem, it is valid to assume the charge is located on the surface, as the electric field outside the sphere behaves the same regardless of whether the charge is uniformly distributed on the surface or throughout the volume. The correct radius of the drop can be calculated using the provided potential and charge values.

PREREQUISITES
  • Understanding of electric potential and its relationship to charge and radius
  • Familiarity with the equation Potential = (1/4πε) q/r
  • Knowledge of Gauss's Law and its implications for electric fields
  • Basic concepts of electrostatics and charge distribution
NEXT STEPS
  • Study the implications of Gauss's Law on electric fields around charged objects
  • Explore the differences between conductors and insulators in electrostatics
  • Learn about the concept of electric potential energy in spherical charge distributions
  • Investigate the behavior of electric fields in non-conductive materials
USEFUL FOR

Students studying electrostatics, physics educators, and anyone interested in understanding electric potential and charge distribution in spherical objects.

mm2424
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Homework Statement



A spherical drop of water carrying a charge of 30 pC has a potential of 500 V at its surface (which V = 0 at infinity). What is the radius of the drop?

Homework Equations



Potential = (1/4εpi) q/r


The Attempt at a Solution



When I first looked at this problem, I assumed that pure water would have charge evenly distributed, since it's not a conductor...and I was confused, because I wasn't sure how to calculate the charge on the surface, which is where the Voltage is given. To answer this problem, do we have to assume that the charge is located on the surface and then use the equation for potential? I did so, and got the right answer. However, I'm not sure whether I am right that we have to make this assumption, or whether there is some larger theoretical issue whereby it doesn't matter whether the charge is on the surface of evenly distributed throughout the sphere.
 
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mm2424 said:

Homework Statement



A spherical drop of water carrying a charge of 30 pC has a potential of 500 V at its surface (which V = 0 at infinity). What is the radius of the drop?

Homework Equations



Potential = (1/4εpi) q/r


The Attempt at a Solution



When I first looked at this problem, I assumed that pure water would have charge evenly distributed, since it's not a conductor...and I was confused, because I wasn't sure how to calculate the charge on the surface, which is where the Voltage is given. To answer this problem, do we have to assume that the charge is located on the surface and then use the equation for potential? I did so, and got the right answer. However, I'm not sure whether I am right that we have to make this assumption, or whether there is some larger theoretical issue whereby it doesn't matter whether the charge is on the surface of evenly distributed throughout the sphere.
What does Gauss's Law tell you about the E-field external to the drop. Does it matter whether the charge is distributed uniformly on the surface or distributed uniformly throughout the volume?
 

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