Arranging Letters of 'Daughter' with Specific Conditions

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SUMMARY

The discussion focuses on arranging the letters of the word "daughter" under specific conditions: ensuring that no two vowels are adjacent and maintaining the relative positions of consonants and vowels. The total arrangements of the letters are calculated as 8!, while the arrangements where at least two vowels are together are computed as 7! multiplied by the permutations of 2 vowels (3P2). The participant expresses confusion over the discrepancy in their answer and seeks clarification on the problem statement.

PREREQUISITES
  • Understanding of permutations and combinations
  • Familiarity with factorial notation
  • Knowledge of vowel and consonant classification in English
  • Basic problem-solving skills in combinatorial mathematics
NEXT STEPS
  • Study advanced combinatorial techniques in arrangements
  • Learn about restrictions in permutations
  • Explore the concept of derangements in combinatorial problems
  • Practice problems involving arrangements with specific conditions
USEFUL FOR

Students studying combinatorial mathematics, educators teaching permutation concepts, and anyone interested in solving complex arrangement problems.

ritwik06
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Homework Statement



Arrange the letters of the word daughter such that
1. no two vowels are together.
2. the relative positions of the consonants and the vowels are not changed.





The Attempt at a Solution


1. Total arrangements =8!
Ways in which at least 2 vowels occur togther=7!*(3P2)
I subtract them, but my answer i different.
2. What does this statement mean?
 
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Have I missed out something guys? Why isn't anybody paying any heed to ma question?
 
ritwik06 said:
Have I missed out something guys? Why isn't anybody paying any heed to ma question?

Mods delete the thread...:cry:
 

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