Finding Entire Functions Satisfying Specific Conditions

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Homework Help Overview

The discussion revolves around finding entire functions that satisfy the condition g(1/n) = g(-1/n) = 1/n². Participants are exploring the nature of these functions within the context of complex analysis.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of the function being entire and its ability to be expressed as a Taylor series. There are hints regarding the even nature of the function and examples of even functions like f(x) = x² and f(x) = cos(x) are mentioned.

Discussion Status

There is an active exploration of the properties of even functions and their relation to the problem. Hints have been provided, but no consensus has been reached on a specific solution or method.

Contextual Notes

Participants note that the condition g(1/n) = g(-1/n) suggests a relationship to even functions, leading to discussions about the types of functions that could satisfy the given condition. The nature of n being even is also under consideration.

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Homework Statement



To find entire functions which satisfy g([itex]\frac{1}{n}[/itex]) = g(-[itex]\frac{1}{n}[/itex]) = [itex]\frac{1}{n^{2}}[/itex]

Homework Equations



How many functions can be found?

The Attempt at a Solution



Because the function is entire, it can be expanded in the Taylor series. But how can I work out the question?
 
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DanniHuang said:

Homework Statement



To find entire functions which satisfy g([itex]\frac{1}{n}[/itex]) = g(-[itex]\frac{1}{n}[/itex]) = [itex]\frac{1}{n^{2}}[/itex]

Homework Equations



How many functions can be found?

The Attempt at a Solution



Because the function is entire, it can be expanded in the Taylor series. But how can I work out the question?

Hint :

This condition here : g([itex]\frac{1}{n}[/itex]) = g(-[itex]\frac{1}{n}[/itex])

Should look oddly familiar to : [itex]g(x) = g(-x)[/itex] which is the definition of an EVEN function.

For example, consider these functions :

f(x) = x^2
f(x) = x^4
...
f(x) = x^2n

;)
 
You should be able to easily find one entire function that satisfies that. A hint might be, 'don't think too hard'.
 
Zondrina said:
Hint :

This condition here : g([itex]\frac{1}{n}[/itex]) = g(-[itex]\frac{1}{n}[/itex])

Should look oddly familiar to : [itex]g(x) = g(-x)[/itex] which is the definition of an EVEN function.

For example, consider these functions :

f(x) = x^2
f(x) = x^4
...
f(x) = x^2n

;)

So n can only be even numbers with the Ʃa[itex]_{n}[/itex]z[itex]^{n}[/itex]=[itex]\frac{1}{n^{2}}[/itex]. And then?
 
DanniHuang said:
So n can only be even numbers with the Ʃa[itex]_{n}[/itex]z[itex]^{n}[/itex]=[itex]\frac{1}{n^{2}}[/itex]. And then?

Not necessarily, consider : cos(x), cosh(x), |x|

Those are all even functions as well.
 
Last edited:

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