Arrow being fired to centre of target

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SUMMARY

The discussion centers on the physics of projectile motion, specifically the calculation of an arrow's trajectory using the SUVAT equations. The key equation used is s = ut + 1/2 at², with initial velocity (u) calculated as 65 sin(4.3°) and time (t) determined to be 1.08 seconds. The acceleration due to gravity is consistently -9.81 m/s², as the upward direction is defined as positive, which clarifies why gravity is treated as negative in this context. This understanding resolves confusion regarding the direction of acceleration during the arrow's flight.

PREREQUISITES
  • Understanding of SUVAT equations in kinematics
  • Basic trigonometry for decomposing velocity vectors
  • Knowledge of gravitational acceleration (g = -9.81 m/s²)
  • Ability to interpret projectile motion problems
NEXT STEPS
  • Study the derivation and application of SUVAT equations in various projectile motion scenarios
  • Learn how to decompose vectors into horizontal and vertical components
  • Explore the concept of coordinate systems in physics, particularly how direction affects calculations
  • Practice solving projectile motion problems with varying angles and initial velocities
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and projectile motion, as well as educators seeking to clarify concepts related to gravity and vector decomposition.

hello478
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Homework Statement
part b and part c of the question
Relevant Equations
suvat equations
i solved it like this...
s = ut + 1/2 at^2
t= 1.08 (from part a)
u= 65 sin4.30
a= 9.81? or -9.81
the answer said -9.81
why? wouldn't acceleration change from -9.81 to +9.81 because it moves up then down???
its soo confusing...

1711481019245.png

1711481043968.png
 
Last edited:
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hello478 said:
Homework Statement: part b and part c of the question
Relevant Equations: suvat equations

i solved it like this...
s = ut + 1/2 at^2
t= 1.08 (from part a)
u= 65 sin4.30
a= 9.81? or -9.81
the answer said -9.81
why? wouldn't acceleration change from -9.81 to +9.81 because it moves up then down???
No, the acceleration wouldn't change unless gravity suddenly reversed.
hello478 said:
its soo confusing...

View attachment 342395
 
Mark44 said:
No, the acceleration wouldn't change unless gravity suddenly reversed.
ok... so why is acceleration -9.81?

i fixed the picture now... 🙃
 
hello478 said:
ok... so why is acceleration -9.81?
Because they're assuming that the "up" direction is positive, and gravity is acting downward.
 
Mark44 said:
Because they're assuming that the "up" direction is positive, and gravity is acting downward.
is it in the question? i cant find it...
 
hello478 said:
is it in the question? i cant find it...
It's not explicitly given. What they tell you is that the speed (i.e., ##|\vec v|##) of the arrow is 65 m/sec, at an angle of 4.3° above horizontal. The arrow's velocity vector can be decomposed into a vertical component and a horizontal component.

The usual approach for problems of this sort is to treat upward velocities as positive, with gravity acting downward (so g = -9.81 m/sec^2). During the flight, the arrow's vertical component of velocity will start off positive, slowly decrease to zero at its high point, and then become negative as it continues on to the target.
 
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ok thank you, i got it now
 

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