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Assume that f is non-negative on (0,1)

  1. Jan 14, 2006 #1
    Hello...I need help and I know this is a very simple problem...I don't know why I'm getting stuck( Maybe because it's past midnight here:frown: )

    Assume that f is non-negative on (0,1) and the third derivative of f exists on (0,1).If f(x)=0 for at least 2 values of x in (0,1), show that there exists "c" in (0,1) such that the third derivative of f at c is 0.

    this is what i've done...let a,b be the points where f vanishes. that is f(a)=f(b)=0
    so we can use Rolle's theorem and get a point p such that f^(p)=0.

    What next??
     
  2. jcsd
  3. Jan 14, 2006 #2

    matt grime

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    draw a picture: hint it is non-negative and touches the x-axis twice (necessarily at local minima)
     
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