MHB Assume that S and T are linear maps from the vector space V to itself.

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To prove that V = X ⊕ Y, where X = range(S) and Y = range(T), it is essential to verify two conditions: that X and Y are subspaces of V and that their intersection is trivial (X ∩ Y = {0}). Given that S + T = Iv indicates that every vector in V can be expressed as a sum of vectors from X and Y, and S ∘ T = Ov = T ∘ S ensures that the mappings are independent, the direct sum condition is satisfied. The discussion emphasizes the need to apply the definition of a direct sum to confirm these properties. Understanding these relationships is crucial for completing the proof.
toni07
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Assume also that S + T = Iv and that S ∘ T = Ov = T ∘ S. Prove that V = X ⊕ Y where
X = range(S) and Y = range(T). I don't understand how to go about it, please help.
 
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crypt50 said:
Assume also that S + T = Iv and that S ∘ T = Ov = T ∘ S. Prove that V = X ⊕ Y where
X = range(S) and Y = range(T). I don't understand how to go about it, please help.
You need to use the definition of the direct sum $X\oplus Y$. The question tells you which subspaces to use for $X$ and $Y$, so what do you have to check in order to show that the definition of $V = X\oplus Y$ is satisfied?
 

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