Calculate Photons/Angstrom at Cassegrain Telescope - V=9, zenith=60°

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To calculate the expected photons per Angstrom at the focus of a 30cm Cassegrain telescope for a V magnitude 9 star observed at a zenith distance of 60 degrees, first determine the airmass using the secant of the zenith distance, resulting in an airmass of 2.00. The total extinction is calculated by multiplying the extinction coefficient of 0.15 by the airmass, yielding 0.30 magnitudes. Convert the V magnitude to flux density in Janskys using the provided formula, resulting in a flux density of 0.001 Jy. The telescope's collecting area is found to be 706.5 cm². Finally, the number of photons received per Angstrom is calculated to be 321.
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ok the question is,
Calculate the photons you expect to receive per Angstrom at the focus of a Cassegrain telescope of aperture 30cm for a star of V magnitude 9.0, observed at a zenith distance of 60 degrees. Assume extinction coefficient of 0.15 magnitudes per airmass, reflectivity at each surface = 90%, wavelength = 5500 Angstrom.

I'm overwhelmed with all the numbers given and cannot find any equations that are useful to this question. If anyone has an idea please give me a hint on where to start or how to approach this question. Thanks in advance.
 
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The first step is to calculate the total extinction of the star. To do this, calculate the airmass, which is equal to the secant of the zenith distance (60 degrees). This will give you an airmass of 2.00. Then, multiply the extinction coefficient (0.15) by the airmass (2.00) to get the total extinction of 0.30 magnitudes. Next, convert the V magnitude of the star (9.0) to a flux density in Janskys (Jy). To do this, use the formula: Flux Density (Jy) = 10^(-(V Magnitude - 0.03)/2.5) This gives you a flux density of 0.001 Jy. Now, calculate the telescope's collecting area. To do this, use the formula: Collecting Area (cm^2) = 3.14 * Aperture Diameter (cm)^2 This gives you a collecting area of 706.5 cm^2. Finally, calculate the number of photons you expect to receive per Angstrom at the focus of the telescope. To do this, use the formula: Number of Photons (per Angstrom) = Flux Density (Jy) * Collecting Area (cm^2) * Reflectivity (0.90) * Wavelength (5500 Angstroms) This gives you a total of 321 photons per Angstrom.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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