Astrophysics - elliptical orbit proof help.

Click For Summary

Homework Help Overview

The discussion revolves around proving the equation of an ellipse and its area, specifically in the context of an elliptical planetary orbit. The original poster expresses confusion regarding the mathematical proofs required for these concepts.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the standard equation of an ellipse and its parameters, questioning the use of specific coordinates and the implications of the equation. There is also exploration of how to derive the area of an ellipse through integration and trigonometric substitution.

Discussion Status

Some participants have provided guidance on identifying the parameters of the ellipse and suggested methods for finding the area. The conversation reflects a mix of attempts to clarify the mathematical concepts involved, with no explicit consensus reached on the proofs.

Contextual Notes

The original poster indicates a sense of being lost in the problem, and there is mention of textbook references that may influence the approach to the proofs. The discussion includes assumptions about the coordinate system and the properties of ellipses.

Kiwithepike
Messages
16
Reaction score
0
A.)
Assume a rectangular coord system has its origin at the center of an elliptical planetary orbit and that the coord system x-axis lies along the major axis of the ellipse. Show that the equation for the ellipse is given by x^2/a^2 + y^2/b^2 =1.
where a and b are the lengths if the semi-major axis and the semi-minor axis, respectively.

b.)
using the results from a, prove the area of an ellipse is given by A=(pi)ab.

Im am completely lost right now. Any ideas?
 
Physics news on Phys.org
For starters, what facts do you know about an ellipse that you could use in the proof?
 
(x-h)^2/a^2 + y-k)^2/b^2=1

c^2= a^2 -b^2

while a ≥b>0
 
OK, well for part a, for the ellipse in question, what would h and k be?
 
zero, so (x-h)^2 = x^2 and (y-k)^2= y^2 right?
 
Right, so that part's done. (Although it seems really simple, are you sure you can use that equation as a starting point?)

Now what about part b? How could you find area?
 
thats what the text tell you to use. That does seem really simple, maybe that's why I am so lost.

B) i know the area A=piab
so the way i was looking at it
solve for y? then integrate it, with trig sub get pi ab?
 
Yep, sounds like you're on the right track with that. (Obviously make sure you actually do it to verify that you get the right answer)
 
Thank you so much for your help
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
9K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
4K
Replies
2
Views
2K