Asymptotic behaviour of bessel functions

Click For Summary
SUMMARY

The discussion centers on the asymptotic behavior of Bessel functions, specifically the relationship expressed in the equation involving \( J_0(i^{\frac{3}{2}}\alpha_n\frac{r}{a}) \) and \( J_0(i^{\frac{3}{2}}\alpha_n) \) when \( \alpha_n >> 1 \). The user identifies a potential mathematical identity related to the exponential term and the arguments of the Bessel functions. The discussion highlights the significance of understanding the manipulation of Bessel function arguments and their asymptotic properties, particularly in the context of complex arguments.

PREREQUISITES
  • Understanding of Bessel functions, particularly \( J_0 \) functions
  • Familiarity with asymptotic analysis in mathematical functions
  • Knowledge of complex numbers and their properties
  • Basic calculus, including exponential functions and limits
NEXT STEPS
  • Study the asymptotic expansions of Bessel functions in detail
  • Learn about the properties of complex arguments in Bessel functions
  • Explore mathematical identities related to Bessel functions and their applications
  • Investigate the role of exponential functions in asymptotic analysis
USEFUL FOR

Students and researchers in mathematics, particularly those focusing on special functions, asymptotic analysis, and complex analysis. This discussion is beneficial for anyone looking to deepen their understanding of Bessel functions and their applications in mathematical physics.

lavster
Messages
213
Reaction score
0
Hi,

as part of my maths course i am learning about bessel functions. But this is something that I am not fully comfortable with - there seems to be a lot of tricks.

There is a statement in my notes that when [tex]\alpha_n>>1[/tex],
[tex]\frac{J_0(i^{\frac{3}{2}}\alpha_n\frac{r}{a})}{J_0(i^{\frac{3}{2}}\alpha_n)} = (\frac{r}{a})^\frac{1}{2}exp[-\sqrt{i}(1-\frac{r}{a}\alpha_n][/tex]

i know that [tex]\sqrt{i}=\pm\frac{1}{\sqrt{2}}(1+i)[/tex], which i think will help show this statement. I've also noticed that the argument in exp[] is the bit in the brackets of the bessl function in the denominator minus the bit in the brackets of the bessel function on the numerator. and the multiplying factor of exp in the RHS sems to me the bits in the brackets of the bessel function deivided by each other...

can anyone tell me if this is merely coincidence or whether there is a mathematical trick or identity that helps to show this?

sorry if this is confusing...

thanks, lav
 
Physics news on Phys.org
there is meant to be an approximately equal sign between the first fraction (inbvolveing the bessel functions) and the fraction with r and a to the power of 1/2...
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
11K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K