At what distance from a carbon nucleus is the electric potential 2.1 V?

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SUMMARY

The discussion focuses on calculating the distance from a carbon nucleus at which the electric potential equals 2.1 V. The relevant equations are identified as V = KQ/r for electric potential, where K is Coulomb's constant and Q represents the total charge of the carbon nucleus, calculated as 6 times the elementary charge. The correct formula for electric potential is confirmed to be V = KQ/r, while V = KQ/r² pertains to electric field calculations. Participants clarify the distinction between these formulas to solve for the distance r.

PREREQUISITES
  • Understanding of electric potential and point charges
  • Familiarity with Coulomb's constant (K)
  • Knowledge of elementary charge (e)
  • Basic algebra for solving equations
NEXT STEPS
  • Study the concept of electric potential in electrostatics
  • Learn about Coulomb's law and its applications
  • Explore the differences between electric potential and electric field
  • Practice solving problems involving point charges and electric potential
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Students studying physics, particularly those focusing on electrostatics, as well as educators looking for examples of electric potential calculations.

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Homework Statement



At what distance from a carbon nucleus is the electric potential 2.1 V? Carbon atoms have 6 electrons in the atomic shell.

Homework Equations



v= K Q / r^2 OR K Q / r (NOT SURE)

The Attempt at a Solution



use voltage potential for point charge

Using either v= K Q / r^2 OR K Q / r (not sure)

V given, Q ( 6* electron charge) , solve for r
 
Last edited:
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It's the forumula with "r" in the denominator. The "r^2" forumula is for the electric field.
 

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