(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 13.0nC charge is at x = 0cm and a -1.1nC charge is at 6cm. At what point or points on the x-axis is the electric potential zero?

Let X_{0}be a position on the x-axis

Let V_{1}be the electrical potential at a point due to the 13nC charge

Let V_{2}be the electrical potential at a point due to the -1.1nC charge

2. Relevant equations

V=k(q)*(1/r); k = Coulomb's constant, q = source charge for which at distance 'r' away, the electrical potential is V volts.

3. The attempt at a solution

There are three possible positions for which the electrical potential is 0:

1) To the left of the 13nC charge

2) Between 13nC charge and -1.1nC charge

3) To the right of the -1.1nC charge

For 1), I took the net voltage: V_{1}+ V_{2}= 0 which is:

K(13E-9)*(X_{0}) + K(-1.1E-9)*(X_{0}) = 0, respectively. Simplifying the sum of two fractional terms, I only needed to find the X_{0}that would make the numerator 0 and thus obtain the X_{0}for which net Voltage is 0.

I applied similar calculation procedures for 2) and 3). My results were that X_{0}= -.0655m, .05532m, .07109m, 1) to 3) respectively.

Attached is a diagram of the problem solving approach I took.

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# Homework Help: At what point on the x-axis is the Electric Potential zero?

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