At what speed must I throw vertically an object.

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astrololo
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Homework Statement


At what speed must I throw vertically an object so that it will lose 25 % of its speed during the first second.

Homework Equations


V final = v initial + a * t

The Attempt at a Solution



v final * 0.75 = v initial + -9.8 m/s^2 * 1 second

That's pretty much what I figured out only ...
 
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Bystander said:
"Only,..." what?
Is there a problem ?
 
Bystander said:
You haven't answered the original question, what's the original vertical speed?
Well that's the thing I have no idea of how to obtain the answwer...
 
Bystander said:
You're interested in the rate at which the object loses speed, and specifically asked for a 25% loss in one second. What's "vfinal" for 100% loss?
Well it's 0.
 
Bystander said:
Substitute that value, and rearrange. What's "v(t=1s)" relative to "vinitial?"
Vi=9,8 m/s
 
Bystander said:
What's "a?"
-9.8 m/s^2
 
Bystander said:
9.8 is what percentage of 9.8?
100%
 
Bystander said:
In one second, the speed changes by how much?
it goes from 9.8 to 0.
 
Bystander said:
No. It changes by 9.8.
Yes, that's what I said. ok, it changes by 9.8.
 
astrololo said:
v final * 0.75 = v initial + -9.8 m/s^2 * 1 second
Fix the left hand side of that equation. Then you should be able to solve for vinitial.
 
Doc Al said:
Fix the left hand side of that equation. Then you should be able to solve for vinitial.
I put it that way so that the speed would be 75%... it's not correct?
 
astrololo said:
I put it that way so that the speed would be 75%... it's not correct?
No, it's not correct.

This is the formula you are trying to use:
astrololo said:
V final = v initial + a * t

Hint: express Vfinal in terms of Vinitial.
 
Doc Al said:
No, it's not correct.

This is the formula you are trying to use:Hint: express Vfinal in terms of Vinitial.
v initial = Vfinal/(a * t)

Vinitial = V final / (-9.8* 1)

Vinitial = V final / -9.8

This is what you want ?
 
astrololo said:
This is what you want ?
No. I want you to fix the left hand side of your equation, just like I asked.

First step: Can you tell me what's wrong with it?
 
Doc Al said:
No. I want you to fix the left hand side of your equation, just like I asked.

First step: Can you tell me what's wrong with it?
Well I multiplied the left side by 75%
So we have v final = v initial + a* t
 
astrololo said:
Well I multiplied the left side by 75%
So we have v final = v initial + a* t
But the left side of your equation was 0.75vfinal, not vfinal. Fix that!
 
Doc Al said:
But the left side of your equation was 0.75vfinal, not vfinal. Fix that!
Ok, so I had v final * 0.75 = v initial + -9.8 m/s^2 * 1 second

and I change it to v final = v initial + -9.8 m/s^2 * 1 second
 
astrololo said:
Ok, so I had v final * 0.75 = v initial + -9.8 m/s^2 * 1 second

and I change it to v final = v initial + -9.8 m/s^2 * 1 second
Good. Now express vfinal in terms of vinitial. (That's where the 0.75 comes in.) That way you can solve for vinitial.
 
Doc Al said:
Good. Now express vfinal in terms of vinitial. (That's where the 0.75 comes in.) That way you can solve for vinitial.
So we have Vf + 9.8 = Vi

I will multiply Vf by 0.75 ?
 
astrololo said:
So we have Vf + 9.8 = Vi

I will multiply Vf by 0.75 ?
No. First things first. Forget about that equation for a moment.

Express vfinal in terms of vinitial. Once you get that correct, then you can go back to the equation.
 
Doc Al said:
No. First things first. Forget about that equation for a moment.

Express vfinal in terms of vinitial. Once you get that correct, then you can go back to the equation.
Sorry, english isn't my first language. You mean that you want V final in function of Vinitial, right ? Like what we had with v final = v initial + -9.8 m/s^2 * 1 second
 
astrololo said:
Sorry, english isn't my first language. You mean that you want V final in function of Vinitial, right ? Like what we had with v final = v initial + -9.8 m/s^2 * 1 second
Forget about that equation for the moment. What I want you to do is express this fact:
astrololo said:
that it will lose 25 % of its speed during the first second.

Then you can combine that with the other equation.