The problem involves two stones thrown vertically upward with the same initial speed of 25.30 m/s, but with a time delay of 1.860 seconds between their launches. The objective is to determine the time at which both stones reach the same height during their trajectories.
The discussion is ongoing, with participants exploring different approaches to the problem. Some guidance has been offered regarding the time to reach maximum height and the need to consider the timing of the second stone's launch. However, there is no explicit consensus on the method to solve the problem.
Participants are working under the constraints of the problem setup, including the initial speeds and the time delay between the launches. There is an emphasis on understanding the motion of both stones throughout their trajectories.
blueskadoo42 said:A stone is thrown vertically upward at a speed of 25.30 m/s at time t=0. A second stone is thrown upward with the same speed 1.860 seconds later. At what time are the two stones at the same height?
what are the equations needed, and any help is greatly appreciated thanks
blueskadoo42 said:i have tried setting them equal.
also, tried using the equation X-Xo= Vox*t + .5Ax*t^2
and Vx^2=Vox^2 + 2 Ax (x-xo)
i can't seem to be getting anything reasonable...
blueskadoo42 said:A stone is thrown vertically upward at a speed of 25.30 m/s at time t=0. A second stone is thrown upward with the same speed 1.860 seconds later. At what time are the two stones at the same height?
what are the equations needed, and any help is greatly appreciated thanks