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Atkisnon's derivation of \gamma factor.

  1. Sep 25, 2012 #1

    MathematicalPhysicist

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    So I am rereading David Atkinson's QFT book:
    http://books.google.co.il/books/about/Quantum_Field_Theory.html?id=vbAnQAAACAAJ&redir_esc=y

    And I am puzzled by what is written in pages 5-6 section 1.3 Special Theory of Relativity.

    He writes down the transformation between two inertial frames, one moving at speed v compared to the other.

    [tex] x'=\gamma (x-vt) \ y'=y \ z'=z[/tex]

    Now he writes on page 6:
    My problem is with the last conclusion, why can't we have \gamma to be any even function of v, like v^4 and so forth?
     
  2. jcsd
  3. Sep 25, 2012 #2
    any even function of v is a function of v^2.

    v^4 = (v^2)^2
     
  4. Sep 25, 2012 #3

    MathematicalPhysicist

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    Feel so stupid now... :-D

    Thanks.
     
  5. Sep 25, 2012 #4
    don't feel bad. everybody misses stuff like that at times.

    in fact you could come back and ask. really? every even function
    of v is a function of v^2? those are two different things in principle,
    even functions f(v) = f(-v) and f(v) = h(v^2) for some h.

    it's not that hard to prove either.
     
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