So I am rereading David Atkinson's QFT book:(adsbygoogle = window.adsbygoogle || []).push({});

http://books.google.co.il/books/about/Quantum_Field_Theory.html?id=vbAnQAAACAAJ&redir_esc=y

And I am puzzled by what is written in pages 5-6 section 1.3 Special Theory of Relativity.

He writes down the transformation between two inertial frames, one moving at speed v compared to the other.

[tex] x'=\gamma (x-vt) \ y'=y \ z'=z[/tex]

Now he writes on page 6:My problem is with the last conclusion, why can't we have \gamma to be any even function of v, like v^4 and so forth? What is gamma?

From the uniformity of space, we see that \gamma may not depend on the coordinates (...).

In the absence of gravity, \gamma is independent of t,x,y,z but it may depend on v.

...

Rotational invariance therefore means that \gamma must be independent of the sign of v, i.e, it's a function only of v^2.

**Physics Forums - The Fusion of Science and Community**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Atkisnon's derivation of \gamma factor.

Loading...

Similar Threads for Atkisnon's derivation gamma | Date |
---|---|

I Riemann curvature tensor derivation | Saturday at 11:27 PM |

A Commutator of covariant derivative and D/ds on vector fields | Mar 15, 2018 |

I Interesting Derivation of Maxwell's Equations | Mar 11, 2018 |

I Latest Gamma Ray Burst Experimental results | Mar 6, 2018 |

A Sean Carroll Notes, Schwarzschild derivation, theorem name? | Mar 5, 2018 |

**Physics Forums - The Fusion of Science and Community**