Atomic/Nuclear Bombs in Space: Oxygen Required?

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Nuclear bombs can be detonated in space without the need for oxygen, as they rely on nuclear reactions rather than chemical combustion. Historical tests, such as the 1962 Starfish Prime, demonstrated the effects of nuclear explosions in space, including the potential for electromagnetic pulses (EMPs) that could disrupt electronics on Earth. Scientists are exploring the use of nuclear weapons to alter the trajectory of asteroids by vaporizing surface material, which creates thrust through the ejected mass. However, some experts argue that kinetic impact methods may be more effective for diverting asteroids than nuclear explosions. Overall, the discussion emphasizes the complexities and potential applications of nuclear technology in space.
  • #31
Bob S said:
I worked at the Nevada Test Site on nuclear tests in 1958 (before Pres. Eisenhower canceled them), and saw firsthand the surface evaporation by radiation. For a given amount of energy release, moving more mass will cause a greater deflection of an asteroid.

Bob S
Very good as I saw nuke explosion only by TV.
Above surface?
Altitude?
Very good if you saw that but has anyone calculated ablation rate? How it dependent on nature of asteroid's matter (iron, ice, etc.)?
 
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  • #32
Morbius said:
HowlerMonkey,

I read the posts. I understand the posts.

Even in a vacuum, there's more going on than just the expansion of matter.

There is one HELL of a radiation wave expansion that makes the matter expansion look trifling.

I CORRECTED your ERROR

I'm not trying to "skewer".

Why not just be glad that you've now learned something.

Dr. Gregory Greenman

Morbius, based your responses, you have misunderstood Howler's point. It is doubly uncool to then expect someone to appreciate how much they've "learned" from you.

No need to go over it all again, just dial back on all the fist-pounding wouldja?

Morbius said:
100% WRONG.
 
  • #33
Bob S said:
I worked at the Nevada Test Site on nuclear tests in 1958 (before Pres. Eisenhower canceled them), and saw firsthand the surface evaporation by radiation. For a given amount of energy release, moving more mass will cause a greater deflection of an asteroid.

Bob S

I don't see what you are getting at here Bob. Are you saying that impacting the asteroid with an equal amount of kinetic energy as a nuke releases in thermal and such is going to cause more of an effect on the asteroid? If so, I agree.
 
  • #34
Let's look at deflecting the asteroid 99942 Apophis, a 1,000-foot (320-meter) asteroid that will swing by Earth at a distance of about 19,000 miles (30,000 kilometers) in 2029. In reviewing the Effects of Nuclear Weapons book, S. Glasstone, third edition, published by the U.S. Dept. of Defense, chapter 6 http://nuclearpathways.org/Docs/pdfs/effects/effects6.pdf

The cratering by a 1 kT device is given vs. depth of blast in plots on pages 255 and 256. For a surface blast, the crater diameter is about 60 feet, and depth is 40 feet. Using the scaling laws in the text, a 1 MT device would produce a crater 475 foot diameter and 320 feet deep. Because there is no fallback of ejecta, all of the removed mass will be ejected at high velocity and contribute to momentum transfer, and help deflect the asteroid.

Bob S
 
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  • #35
Bob S said:
Let's look at deflecting the asteroid 99942 Apophis, a 1,000-foot (320-meter) asteroid that will swing by Earth at a distance of about 19,000 miles (30,000 kilometers) in 2029. In reviewing the Effects of Nuclear Weapons book, S. Glasstone, third edition, published by the U.S. Dept. of Defense, chapter 6 http://nuclearpathways.org/Docs/pdfs/effects/effects6.pdf

The cratering by a 1 kT device is given vs. depth of blast in plots on pages 255 and 256. For a surface blast, the crater diameter is about 60 feet, and depth is 40 feet. Using the scaling laws in the text, a 1 MT device would produce a crater 475 foot diameter and 320 feet deep. Because there is no fallback of ejecta, all of the removed mass will be ejected at high velocity and contribute to momentum transfer, and help deflect the asteroid.

Bob S
I see that this is was investigated. But you did not answered on question:
Above surface?
 
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  • #36
Bob I don't see how that relates to the nuke vs high speed kinetic impact question. Perhaps I misunderstood one of your posts?
 
  • #37
Drakkith said:
Bob I don't see how that relates to the nuke vs high speed kinetic impact question. Perhaps I misunderstood one of your posts?
Simply. Bob states that kinetic hit would be ineffective and nuke blast yes - effective.
But he did not answer embodiment method:
• how to carry nuke charge to asteroid?
• at what altitude or after hit detonation should be? As I am afraid that if after hit, simply nuke device will be destroyed without detonation.
• Or there is planed to do as in Armageddon movie - to send two teams of oil well drillers on two Shuttles
 
  • #38
Drakkith said:
Bob I don't see how that relates to the nuke vs high speed kinetic impact question. Perhaps I misunderstood one of your posts?
Drakkith
The basic question is how a 1MT nuclear device with blast energy but without any kinetic energy could deflect or slow down asteroid 99942 Apophis. The secret is

a) A nuclear device placed on the surface of the asteroid, without drilling, can create a significant crater. For this you need to read chapter 6 of Glasstone's book The Effects of Nuclear Weapons (which gave you the link to in my prior post), and in particular review the plots of the crater size vs. depth of blast on pages 255 and 256. For zero depth of a 1 MT device, the crater is over 300 feet deep. So a lot of mass is ejected.

b) The laws of physics (Newton's laws) require that both energy and momentum are conserved.

OK, now for the details. Assume that the mass of the asteroid is M = 8.6 x 107 tonnes (metric tons), and it has a velocity of 24,000 meters per second. Suppose the ejected mass from the crater is m1=3.7 x 104 tonnes. So the remaining mass of the asteroid is M-m1. Further, assume 10% of 1 MT, or 4.7 x 1014 joules, is converted to kinetic energy of the two masses (E1+E2 = Etotal).

Suppose the device is placed on the front of the astrroid, so the ejected mass is accelerated, and the remaining mass of the asteroid is decellerated.

Assignment: You have two equations in two unknowns (v1 and v2).

½m1v12 + ½(M-m1)v22 = 4.7 x 1014 joules

m1v1 = -(M-m1)v2

How much is the asteroid slowed down? Suppose a 10 MT device were used instead?

Bob S
 
  • #39
Joseph Chikva said:
Simply. Bob states that kinetic hit would be ineffective and nuke blast yes - effective.
But he did not answer embodiment method:
• how to carry nuke charge to asteroid?
• at what altitude or after hit detonation should be? As I am afraid that if after hit, simply nuke device will be destroyed without detonation.
• Or there is planed to do as in Armageddon movie - to send two teams of oil well drillers on two Shuttles
Didn't we put two rover vehicles (Spirit and Opportunity) on the surface of Mars, and 3 astronauts on the surface of the Moon? How hard is it to gently place a 1 MT nuclear device on the surface of an asteroid? The only major interplanetary vehicle landing problems we have had (Mars Polar Lander) was that the landing (retrorocket) parameters were specified (by Lockeed Martin) in English units, and the NASA people used metric units. So what is your concern?

Bob S
 
  • #40
Bob S said:
Didn't we put two rover vehicles (Spirit and Opportunity) on the surface of Mars, and 3 astronauts on the surface of the Moon? How hard is it to gently place a 1 MT nuclear device on the surface of an asteroid? The only major interplanetary vehicle landing problems we have had (Mars Polar Lander) was that the landing (retrorocket) parameters were specified (by Lockeed Martin) in English units, and the NASA people used metric units. So what is your concern?

Bob S

Our failure rate on getting probes to Mars is 50%, and that's a large, stable, relatively non-randomly-rotating target.
 
  • #42
DaveC426913 said:
Our failure rate on getting probes to Mars is 50%, and that's a large, stable, relatively non-randomly-rotating target.
Except for the '92-93 Observer mission, all the http://en.wikipedia.org/wiki/Exploration_of_Mars#Timeline_of_Mars_exploration" with a successful launch arrived at Mars. I doubt the landing issues that plagued a couple of the missions are relevant to the delivery of a nuclear weapon targeted at an astronomical body with no atmosphere and negligible gravity.
 
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  • #43
Bob, I think we were on different pages here lol. I fully agree with you. I was talking about the effectiveness of a nuke vs a high speed impact of an object. I think it is MUCH easier to use a nuke as the amount of energy generated against the asteroid per fuel used to get it there is much greater than shooting something at it. But I was unsure of how effective a nuke would be. Thanks for the posts though, very insightful.
 
  • #44
Bob S said:
Didn't we put two rover vehicles (Spirit and Opportunity) on the surface of Mars, and 3 astronauts on the surface of the Moon? How hard is it to gently place a 1 MT nuclear device on the surface of an asteroid? The only major interplanetary vehicle landing problems we have had (Mars Polar Lander) was that the landing (retrorocket) parameters were specified (by Lockeed Martin) in English units, and the NASA people used metric units. So what is your concern?

Bob S
Ok, thanks.
Now I understand your statement.
No interception as usually the approaching enemy aircraft or ballistic missile intercepted (high speed hit – up to 3M and in space higher) but gentle landing on surface.
I understand but think that landing on small target would be a big challenge.
And sure that the momentum which asteroid should acquire as result of nuke blast can be easily acquired also by kinetic hit as well. And it seems me as more easy, rational and reliable way.
 
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  • #45
mheslep said:
...targeted at an astronomical body with no atmosphere and negligible gravity.

I think you're making a mistake simplifying it. We're pretty familiar with planetary probe procedures and yet we still have a high screw up rate. We have very littel experience landing on small tumbling bodies whose orbits are not nice, neat and low eccentricity and whose delta v is quite different from Earth's.

I think the ways it's more difficult outnumber the ways it's easier.
 
  • #46
Joseph Chikva said:
...And sure that momentum asteroid should acquire as result of nuke blast can be easily acquired also by kinetic hit as well. And it seems me as more easy, rational and reliable way.
Hi Joseph.
If I work out my kinematics as proposed, the asteroid is slowed down by about 2 meters per second, which is about the minimum needed (corresponds to 39,000 miles per year.).

If a 10 tonne kinematic mass traveling 24,000 meters per second (relative velocity) hits the the 8.7 x 107 tonne asteroid head on, it will slow down the asteroid by only 0.003 meters per second. Not nearly enough. Do you agree?

Bob S
 
  • #47
So...you are saying we need superman then? Or a nuke.
 
  • #48
Bob S said:
Hi Joseph.
If I work out my kinematics as proposed, the asteroid is slowed down by about 2 meters per second, which is about the minimum needed (corresponds to 39,000 miles per year.).

If a 10 tonne kinematic mass traveling 24,000 meters per second (relative velocity) hits the the 8.7 x 107 tonne asteroid head on, it will slow down the asteroid by only 0.003 meters per second. Not nearly enough. Do you agree?

Bob S
Hi Bob,
I thought not to slow down asteroid but to give to asteroid some radial (angular) momentum.
As distances (Earth - defending object vs. asteroid - attacking object) are high and dimensions are low, deflecting only on very small angle is required.
 
  • #49
DaveC426913 said:
I think you're making a mistake simplifying it. We're pretty familiar with planetary probe procedures and yet we still have a high screw up rate.
The record for the US shows otherwise, given a successful launch and given the probe doesn't have to land
We have very littel experience landing on small tumbling bodies whose orbits are not nice, neat and low eccentricity and whose delta v is quite different from Earth's.
Why land a nuclear weapon on the surface, and why would the body's spin rate matter?
 
  • #50
mheslep said:
... given the probe doesn't have to land
Why land a nuclear weapon on the surface, and why would the body's spin rate matter?

I refer you back to Bob S' post, where the question was asked:

Bob S said:
How hard is it to gently place a 1 MT nuclear device on the surface of an asteroid?

i.e.: land
 
  • #51
Drakkith said:
So...you are saying we need superman then? Or a nuke.
We can deliver lots of blast energy (nuke) but negligible kinetic energy to the asteroid. To slow down or deflect the asteroid, we need momentum transfer. So blast energy has to be converted to momentum. Newton says p2 = 2ME. So the blast has to move as much mass as possible.

Bob S
 
  • #52
What might be required so that the asteroid is fragmented into parts small enough to burn up in Earth atmosphere?
 
  • #53
mheslep said:
What might be required so that the asteroid is fragmented into parts small enough to burn up in Earth atmosphere?

Very difficult to ensure it ALL gets reduced to small enough pieces. And simulations show that it is possible the many smaller hits could have a much worse effect than one large one.

This the the riskiest of all options.
 
  • #54
Bob S said:
We can deliver lots of blast energy (nuke) but negligible kinetic energy to the asteroid. To slow down or deflect the asteroid, we need momentum transfer. So blast energy has to be converted to momentum. Newton says p2 = 2ME. So the blast has to move as much mass as possible.

Bob,

The kinetic energy delivered to the asteroid is NOT NEGLIGIBLE. In fact, by ablating the surface of the asteroid, the amount of kinetic energy / momentum imparted to the asteroid beats anything that a rocket or "impactor" can do by orders of magnitude.

As was stated in the article on Dr. Dearborn that I referenced earlier - if the object is large or the time scale to deflect it is short - then nuclear weapons are our ONLY methodology, and our only hope.

Dr. Gregory Greenman
 
  • #55
Joseph Chikva said:
Simply. Bob states that kinetic hit would be ineffective and nuke blast yes - effective.
But he did not answer embodiment method:
• how to carry nuke charge to asteroid?
• at what altitude or after hit detonation should be? As I am afraid that if after hit, simply nuke device will be destroyed without detonation.
• Or there is planed to do as in Armageddon movie - to send two teams of oil well drillers on two Shuttles

You carry it on a missile. The majority of the work is to get to Earth orbit. For the Moon mission, getting to Earth orbit required the large first and second stages of the Saturn V.
The energy to get from Earth orbit to the Moon was delivered by the relatively modest third stage.

We have missiles that can carry a multiple warhead payload to high, but suborbital trajectory. If we reduced the payload to a single warhead, we can send the warhead a great distance.

The distance is many miles. The optimal distance is a certain fraction of the object's "diameter". I don't think the warhead is going to be in danger of being damaged before detonation, and those warheads were made to be reliable.

Dr. Dearborn shows scenes from Armageddon in his seminars as an example of what NOT to do.

Dr. Gregory Greenman
 
  • #56
Joseph Chikva said:
And sure that the momentum which asteroid should acquire as result of nuke blast can be easily acquired also by kinetic hit as well. And it seems me as more easy, rational and reliable way.

Joe,

Kinetic kill vs nuclear weapon was very heavily studied by LLNL back in the 1990s.

The nuclear weapon can deliver orders of magnitude more energy than can a kinetic kill.

The idea is we want to change the orbit of the asteroid, and that takes energy. If the asteroid is large, we have no way with our chemical rockets to put enough energy into a kinetic kill vehicle to be able to deflect a very large asteroid.

Again, for very large asteroids, or very short time for deflection; the nuclear weapon is the ONLY viable option. It beats kinetic impactors, "gravity tractors"... hands down.

One of the other problems with kinetic kill is that many of the asteroids are what are called "rubble piles". They are not one rock, but a bunch of rocks held loosely together by mutual gravity. A kinetic kill will deflect the rock it hits in a rubble plie, but won't deflect the bulk of the others. The only force between the impacted rock and some of the others is gravity, and gravity is too weak for the short time scale to impart enough momentum.

Dr. Gregory Greenman
 
  • #57
HowlerMonkey said:
Your post stated what my earlier post stated and now you are adding an angle not mentioned in your earlier post where you attempted to correct me by restating almost exactly what I had posted.

This is called a spin.

NO - your feeble attempt above is "spin". If you "think" that what you posted is exactly what I did - then you still don't understand it. Shall we recall what you posted in post #9:

If a nuke is detonated in the near perfect vacuum of space, there isn't anything more than the matter contained within the bomb itself that will expand."

This is WRONG since you state "there isn't anything more than the matter contained within the bomb itself that will expand".

I CORRECTED that by saying there is a lot more to a nuclear explosion in space than just the expansion of bomb debris. There is one hell of a lot of energy contained in the accompanying radiation wave.

More to the point, it's the energy of that radiation, and not the energy of the expanding debris that is used to deflect asteroids. So you left out the most important part about deflecting asteroids, and now you arrogantly say that your representation is exactly the same as what I am saying.

Dr. Gregory Greenman
 
  • #58
Drakkith said:
Even if the warhead was detonated on the surface of the asteroid only about half of the blast would be absorbed by it anyways. Detonating 100 ft above the surface would provide almost the same effect I think.

Dr Dearborn calculates the optimal height for maximal effect, and if memory serves the optimal distance is measured in miles and not feet.

Dr. Gregory Greenman
 
  • #59
Morbius said:
You carry it on a missile. The majority of the work is to get to Earth orbit. For the Moon mission, getting to Earth orbit required the large first and second stages of the Saturn V.
The energy to get from Earth orbit to the Moon was delivered by the relatively modest third stage.

We have missiles that can carry a multiple warhead payload to high, but suborbital trajectory. If we reduced the payload to a single warhead, we can send the warhead a great distance.

The distance is many miles. The optimal distance is a certain fraction of the object's "diameter". I don't think the warhead is going to be in danger of being damaged before detonation, and those warheads were made to be reliable.

Dr. Dearborn shows scenes from Armageddon in his seminars as an example of what NOT to do.

Dr. Gregory Greenman
So, your statement is to explode nuke warhead carried on interceptor missile after hit?

If so:
• What deceleration that warhead will experience after hit before explosion?
• And admissible deceleration for reliable operation of mechanisms?

And I doubt that existing MCBMs can be used. I am sure that new interceptor should be developed. That would not be a problem on base of just today's technology. But that will be a new missile much more agile than MCBM.
 
  • #60
Morbius said:
Joe,

Kinetic kill vs nuclear weapon was very heavily studied by LLNL back in the 1990s.

The nuclear weapon can deliver orders of magnitude more energy than can a kinetic kill.

The idea is we want to change the orbit of the asteroid, and that takes energy. If the asteroid is large, we have no way with our chemical rockets to put enough energy into a kinetic kill vehicle to be able to deflect a very large asteroid.

Again, for very large asteroids, or very short time for deflection; the nuclear weapon is the ONLY viable option. It beats kinetic impactors, "gravity tractors"... hands down.

One of the other problems with kinetic kill is that many of the asteroids are what are called "rubble piles". They are not one rock, but a bunch of rocks held loosely together by mutual gravity. A kinetic kill will deflect the rock it hits in a rubble plie, but won't deflect the bulk of the others. The only force between the impacted rock and some of the others is gravity, and gravity is too weak for the short time scale to impart enough momentum.

Dr. Gregory Greenman
Ok, thanks.
 

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