How do u calculate the atomic spacing on an iron cube? Can someone please help me!!
You mean iron with a cubic lattice?
And what do you know? You cannot calculate anything unless you start with something you know.
OK. Let's consider a 56 gram cube of iron. Using a density of 7.9 grams per cc, this cube is about 7.1 cubic cm. It contains Avagadro's nomber of atoms, or 6.0 x 10^23 atoms. So the volume of one atom is about 1.2 x 10^-23 cm^3. Therefore the linear dimension is the cube root, or 2.3 x 10^-8 cm, or about 2.3 Angstroms (0.23 nanometers).
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