1. The problem statement, all variables and given/known data Physics for Scientists and Engineers, 8th Edition, Ex. 47 M4 A spacecraft flies from 24.000 ft to 31.000 ft, in which it enters a parabolic trajectory with a velocity of 143 m/s at an angle of 45, above the horizontal. It exits with a velocity of 143 m/s at an angle of 45 bellow the horizontal. In that part of its flight, the spacecraft is in a "free fall" ; the astronauts and equipment fly as if there's no gravity. a) What's the magnitude of the Velocity [...] b) [...] and the height of the spacecraft at the maximum height of the maneuver? c) For how much time do the zero g conditions apply? Translation: Left Side: Height (ft) Bottom Horizontal: Time of Maneuver (s) First Part: Lifting of snoot at 45 Second Part: Zero g Third Part: Lowring of snoot at 45 2. Relevant equations Yf=Yi + Viy*t + 1/2*a*t^2 Vf=Vi + a*t Xf=Xi + a*t 3. The attempt at a solution I'm gonna be honest here, I have no clue what to do. At first I thought that it started at 24k ft with 143 m/s, so I set out to find his Velocity at 31k ft, but obviously that was wrong. The I figured that since there's no gravity while it's in the parabolic trajectory, it'd have a constant speed of V = Vi*sin(45) = 101,1 m/s which is close enough to the book's answer (101 m/s). Thing is, I can't for the life of me get how in zero g environment, a spacecraft could reach a bigger height and then start falling again. I'm obviously missing some key component, so I'd greatly appreciate any kind of help.