Atwood Machine: Find m1's Descent and Velocity

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SUMMARY

The discussion centers on solving an Atwood machine problem involving two masses, m1 = 2.00 kg and m2 = 7.50 kg, with m1 initially moving downward at vi = 2.80 m/s. To determine the distance m1 descends and its velocity after 1.80 seconds, participants suggest using Newton's second law (f = ma) and the kinematic equation (vf^2 = v^2 + 2ad). The acceleration can be calculated using the formula a = (g * m1 + g * m2) / (m1 + m2), followed by applying the kinematic equations to find the required values.

PREREQUISITES
  • Understanding of Newton's second law (f = ma)
  • Familiarity with kinematic equations, specifically vf^2 = v^2 + 2ad
  • Basic knowledge of gravitational force (g)
  • Ability to draw and analyze free-body diagrams
NEXT STEPS
  • Calculate the acceleration of an Atwood machine using a = (g * m1 + g * m2) / (m1 + m2)
  • Apply kinematic equations to find displacement and final velocity in motion problems
  • Explore energy conservation methods in Atwood machine scenarios
  • Practice drawing free-body diagrams for multi-mass systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for practical examples of Atwood machine problems.

physics_geek
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Homework Statement


In the Atwood machine shown below, m1 = 2.00 kg and m2 = 7.50 kg. The masses of the pulley and string are negligible by comparison. The pulley turns without friction and the string does not stretch. The lighter object is released with a sharp push that sets it into motion at vi = 2.80 m/s downward.
(a) How far will m1 descend below its initial level?

(b) Find the velocity of m1 after 1.80 s.

Homework Equations


f= ma
vf^2 = v^2 + 2ad

The Attempt at a Solution


i think for part a u use the equation i put above..but i don't know how to figure out acceleration...but i think its splitted between the two objects
 
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Hi physics_geek,

physics_geek said:

Homework Statement


In the Atwood machine shown below, m1 = 2.00 kg and m2 = 7.50 kg. The masses of the pulley and string are negligible by comparison. The pulley turns without friction and the string does not stretch. The lighter object is released with a sharp push that sets it into motion at vi = 2.80 m/s downward.
(a) How far will m1 descend below its initial level?

(b) Find the velocity of m1 after 1.80 s.

Homework Equations


f= ma
vf^2 = v^2 + 2ad

The Attempt at a Solution


i think for part a u use the equation i put above..but i don't know how to figure out acceleration...but i think its splitted between the two objects


To find the acceleration, start by drawing force diagrams for each of the objects. Using \sum F = m a for each of the diagrams then gives two equations with two unknowns.

(You can also use an energy appoach here.)
 
Use the formula a= (gm1 + gm2)/(m2+m1) to find the acceleration then use the formula V^2=-2ad to find the distance. Bada bing bada boom!
Im still workin on the second part unfortunately...
 

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