Augmented Matrices: 0,7,3,1,alpha,-2

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The discussion centers on the construction and row reduction of an augmented matrix represented by the values 0, 7, 3, 1, alpha, and -2. Participants clarify that the matrix should be constructed from the linear equations and that alpha represents a specific entry in the reduced-row form of the matrix. The matrix in question is not the inverse matrix but rather the result of applying row operations to achieve the desired form. The final value of alpha is determined from the entry in row 2, column 3 of the reduced matrix.

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Ry122
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How is this an augmented matrix?
Shouldn't 0 and 7 be 3 and 1 and alpha be -2?
http://users.on.net/~rohanlal/Untitled-1.jpg
 
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The problem says associated augmented matrix.

Yes, construct the augmented matrix just as you say, then row-reduce to what they show. What is alpha?
 
What is the matrix that is shown? Is it the inverse matrix?



What is alpha?

http://en.wikipedia.org/wiki/Alpha_(letter )
 
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Ry122 said:
What is the matrix that is shown? Is it the inverse matrix?





http://en.wikipedia.org/wiki/Alpha_(letter )

:smile:

I think he meant what is the alpha value when you transform your original augmented matrix to the final one (just do some row ops)
 
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No, it's not the inverse matrix. That matrix is obtained when you express the 2 linear equations in the form of a matrix:

\left(\begin{array}{ccc}1&-2&1\\3&1&-2\end{array}\right)

EDIT: I have no idea how to draw the vertical line in the matrix to represent an augmented matrix.

From here you just use row operations to get the matrix in the form given by the question. Alpha is then the value of whatever you have in entry row 2 column 3 of your reduced-row matrix
 

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