The acceleration of a particle moving only on a horizontal xy plane is given by a= (3t)i + (4t)j, where 'a' is in m/s*2 and t is in seconds. At t=0, the position vector r= (20m)i + (40m)j locates the particle, which then has the velocity vector v=(5m/s)i + (2m/s)j. At t=4.00s what are (1)the position vector in unit vector notation and (2) the angle between its direction of travel and the positive direction of the x-axis???
Can someone please help me i'm having a bit of problems with vector question such as this i tried a few things but it was to no use. Any help would be much appreciated :)