Average acceleration of a car changing speed and direction

Click For Summary
To calculate the average acceleration of a car changing speed and direction, one must perform vector subtraction on the two given velocity vectors, maintaining the result as a vector. After obtaining the resultant vector, divide it by the time interval of 8 seconds to find the average acceleration. This method effectively accounts for both changes in speed and direction. Understanding vector operations is crucial for accurate calculations in physics. The discussion highlights the importance of vector analysis in determining average acceleration.
danielsmith123123
Messages
26
Reaction score
4
Homework Statement
A car, travelling initially at 28 m/s [W25 ̊N], takes 8 s to change its velocity to 25 m/s [S]. What is the average acceleration over this time interval?
Relevant Equations
a = vf-vi / t
Nevermind I found what I had to do, thank you though.
 
Physics news on Phys.org
You basically have to do one vector subtraction (subtract the 2 given vectors of velocity and keep the result as vector) and then 1 division by 8sec.
 
Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

Similar threads

  • · Replies 3 ·
Replies
3
Views
899
Replies
20
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
11
Views
1K
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 25 ·
Replies
25
Views
1K
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K