How Do Nitrogen Molecules Accelerate and Exert Force on a Wall?

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The discussion focuses on calculating the average acceleration of a nitrogen molecule and the force it exerts on a wall upon impact. Given the molecule's speed of 6.70 x 10^2 m/s and mass of 4.68 x 10^-26 kg, the average acceleration can be determined using the formula a = Δv/Δt, where Δv is the change in velocity and Δt is the time interval of 1.80 x 10^-13 s. Participants suggest looking for equations related to accelerated motion, emphasizing the importance of understanding initial and final velocities. Resources are shared for further exploration of kinematics and motion equations. The conversation highlights the need for foundational knowledge in physics to solve the problem effectively.
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Homework Statement



The average speed of a nitrogen molecule in air is about 6.70 multiplied by 102 m/s, and its mass is about 4.68 multiplied by 10-26 kg.

(a) If it takes 1.80 multiplied by 10-13 s for a nitrogen molecule to hit a wall and rebound with the same speed but moving in an opposite direction (assumed to be the negative direction), what is the average acceleration of the molecule during this time interval?


(b) What average force does the molecule exert on the wall?

Homework Equations


I have no idea


The Attempt at a Solution


I don't even know how to attempt
 
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We can't help much without seeing some effort from you.
It is accelerated motion. Have you any formulas for accelerated motion? Look for one with a change in velocity, Δv or Vf - Vi in it because you are given those values.
 
Obviously I've already exhausted all the resources I have and all the methods I've tried do not work or else I would not be here...the only formula I have with that is v^2-v_0^2=2a(x-x_0) but I don't have x...not sure what v and v_0 are either..
 
There is a decent set of equations here: http://hyperphysics.phy-astr.gsu.edu/hbase/acons.html

Note that it uses V and Vo instead of Vf and Vi.
It says "acceleration is the slope on the velocity graph", which means a = Δv/Δt, a nice variation on the formulas it has with the V and Vo. Think of Δv as Vf - Vi. And Δt is just t if you are starting out at time zero.

There is a nice set of formulas and their derivations here:
http://en.wikiversity.org/wiki/Motion_-_Kinematics#Motion_with_constant_acceleration
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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