Average Kinetic Energy of molecules calculation

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Homework Help Overview

The discussion revolves around calculating the average kinetic energy of molecules, specifically focusing on hydrogen and nitrogen molecules, and the associated temperature estimations. Participants are examining the implications of using different atomic masses in these calculations.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to reconcile the mass of individual atoms versus molecules in kinetic energy calculations. There is confusion regarding the definition of 'particle' in the context of the problem, and whether to consider hydrogen as H2 or nitrogen as N2. Some participants question the validity of using a small sample size to estimate temperature.

Discussion Status

The discussion is active, with multiple interpretations being explored regarding the mass of particles and the definitions used in the calculations. Some participants have offered clarifications about the nature of the particles involved, while others express uncertainty about the assumptions made in the problem.

Contextual Notes

There is a noted discrepancy between the solution book's answers and participants' calculations, particularly regarding the treatment of hydrogen and nitrogen molecules. The original poster highlights confusion stemming from the problem's wording and the assumptions about molecular composition.

tahmidbro
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Homework Statement
a) what is the rms speed of four hydrogen molecules with the speeds of 890, 755, 902, 866m/s?



Ans : 855m/s



My problem is part b)



b) at what temperature would these hydrogen molecules be?

( Mass of H atom = 1.67 x 10^(-27) kg )



Now, in 1/2m<c^2> = (3/2)kt, should I use the mass for only 1 hydrogen atom, or mass of 2 hydrogen atoms, or the mass for all 8 atoms in 4 molecules?
Relevant Equations
1/2m<c^2> = 3/2kT
the answer in the solution book is 29K which only comes if I use mass for only one atom. ( They did not show any working )

My attempt:

1/2 x (1.67 x 10^(-27)) x (355)^(2) = 3/2 x 1.38 x 10^(-23) x T
T = 29.48820652 K

The confusion arises when I tried the following question:

Q. Estimate the rms speed of the molecules of air in this room.

The answer given in the solution book :

Estimate of 20 °C (T = 293 K); assume all molecules are dinitrogen, so m = 4.676 × 10^(–26) kg; gives rms = 509m/s.
which is only possible if I use mass of two nitrogen atoms.

Please help :-)
 
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The question says hydrogen molecules, so the mass is that of 2 H atoms. Looks like the book got it wrong.
 
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tahmidbro said:
The answer given in the solution book :

Estimate of 20 °C (T = 293 K); assume all molecules are dinitrogen, so m = 4.676 × 10^(–26) kg; gives rms = 509m/s.
which is only possible if I use mass of two nitrogen atoms.

Hi. The solution-book is correct. When you use$$\text{average kinetic energy per particle = }\frac {3}{2}kT$$you have to consider what a 'particle' is.

'Particle' doesn't necessarily mean an atom. A 'particle' in this context is an object which freely moves around and doesn't exert a force on other particles (except during collisions). Not a rigorous definition though!

The question says "assume all molecules are dinitrogen". You are being told that each 'particle' is a nitrogen molecule (N₂).

You can't treat individual atoms as moving around independently because they are moving around in pairs.
 
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Steve4Physics said:
Hi. The solution-book is correct. When you use$$\text{average kinetic energy per particle = }\frac {3}{2}kT$$you have to consider what a 'particle' is.

'Particle' doesn't necessarily mean an atom. A 'particle' in this context is an object which freely moves around and doesn't exert a force on other particles (except during collisions). Not a rigorous definition though!

The question says "assume all molecules are dinitrogen". You are being told that each 'particle' is a nitrogen molecule (N₂).

You can't treat individual atoms as moving around independently because they are moving around in pairs.

Actually, ''dinitrogen'' is not part of the second question. It was part of the answer from solution book.
 
Steve4Physics said:
Hi. The solution-book is correct. When you use$$\text{average kinetic energy per particle = }\frac {3}{2}kT$$you have to consider what a 'particle' is.

'Particle' doesn't necessarily mean an atom. A 'particle' in this context is an object which freely moves around and doesn't exert a force on other particles (except during collisions). Not a rigorous definition though!
The question concerns hydrogen molecules, therefore H2, so the mass of a particle is twice that of a hydrogen atom. The temperature thus obtained differs from that of the textbook.
 
I have some doubts. It happens I know the speed of just four molecules and, from those four values, I can say temperature is T? I understand the first part is about computing the RMS value but the second part leads the reader to believe it's OK to use a sample that small.
 
DrClaude said:
The question concerns hydrogen molecules, therefore H2, so the mass of a particle is twice that of a hydrogen atom. The temperature thus obtained differs from that of the textbook.

DrClaude said:
The question concerns hydrogen molecules, therefore H2, so the mass of a particle is twice that of a hydrogen atom. The temperature thus obtained differs from that of the textbook.
Apologies for the confusion. I was looking at the part of the post relating to air. not hydrogen.
 
tahmidbro said:
Actually, ''dinitrogen'' is not part of the second question. It was part of the answer from solution book.
The question talks about "air", which consists mostly of dinitrogen (and the rest mostly of dioxygen, which is quite similar in mass to dinitrogen).Even physicists are assumed to know that much chemistry. Assuming it's all N2 will give a good estimate.
 

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