Average crush force exerted on a car

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Mathbather
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Homework Statement


Two-panel diagram of a car moving toward a vertical barrier, labelled L1 and L2 for the distances from the barrier to the car's front before and after a head-on crash. The crushed front of the car is shown in the second panel, and the text reads: d = L1 - L2 for the crush distance.



Homework Equations


Kinetic energy = Ke = (1/2)(mv^2) (joules - J)
where m = mass (kg)
v = velocity (m/s)

The Attempt at a Solution


What I was thinking was that the kinetic energy is divided uniformly over the distance d and hence
Average crush force = mv^2 / 2d

But I don't know how to prove that. Of course I could try to explain it with words, but I don't feel that it is enough.

Thank you in advance.
 
All of the KE is converted to work in crushing things: W = Fd = 1/2*m*v^2