# Average current produced by pacemaker

## Homework Statement

Pacemakers designed for long-term use commonly employ a lithium-iodine battery capable of supplying 0.42 A*h of charge.
b) If the average current produced by the pacemaker is 5.6 uA what is the expected lifetime of the device?

C = A/s

## The Attempt at a Solution

I solved for s. s = C/A = 5.6e6A (not sure if i converted that right) / .42 = 1.33e7 s. The thing is, I'm not sure how to convert this to years. thanks for the help

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rl.bhat
Homework Helper

Life time = 0.42A*h/5.6*10^-6A =...........h.

you cant convert seconds to years? You can do one of two things. Divide by seconds in a minute, divide by minutes in an hour, divide by hours in a day, then divide by days in a year. or you could search on google, "convert seconds to years" and then find the answer that way.

yeah i can but i wasn't really sure if i did the first part right and used the correct equation in the first place

ahh okay. i have no idea either

rl.bhat
Homework Helper

yeah i can but i wasn't really sure if i did the first part right and used the correct equation in the first place
Capacity of battery is given in Ampere-hour.
Therefore the life of the battery is given by (Ampere-hour)/ current drawn from the battery.

im getting like 75000 yrs. that cant be right huh?

cepheid
Staff Emeritus