Average current produced by pacemaker

  • Thread starter matt72lsu
  • Start date
  • #1
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Homework Statement


Pacemakers designed for long-term use commonly employ a lithium-iodine battery capable of supplying 0.42 A*h of charge.
b) If the average current produced by the pacemaker is 5.6 uA what is the expected lifetime of the device?


Homework Equations



C = A/s

The Attempt at a Solution


I solved for s. s = C/A = 5.6e6A (not sure if i converted that right) / .42 = 1.33e7 s. The thing is, I'm not sure how to convert this to years. thanks for the help
 

Answers and Replies

  • #2
rl.bhat
Homework Helper
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Life time = 0.42A*h/5.6*10^-6A =...........h.
 
  • #3
1,033
1


you cant convert seconds to years? You can do one of two things. Divide by seconds in a minute, divide by minutes in an hour, divide by hours in a day, then divide by days in a year. or you could search on google, "convert seconds to years" and then find the answer that way.
 
  • #4
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yeah i can but i wasn't really sure if i did the first part right and used the correct equation in the first place
 
  • #5
1,033
1


ahh okay. i have no idea either
 
  • #6
rl.bhat
Homework Helper
4,433
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yeah i can but i wasn't really sure if i did the first part right and used the correct equation in the first place
Capacity of battery is given in Ampere-hour.
Therefore the life of the battery is given by (Ampere-hour)/ current drawn from the battery.
 
  • #7
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im getting like 75000 yrs. that cant be right huh?
 
  • #8
cepheid
Staff Emeritus
Science Advisor
Gold Member
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You know, if you keep the charge in amp-hours, it'll make things easier, because the time you calculate will automatically be in hours. All you have to do is convert the current from microamps to amps. This is easy, because a microamp is a millionth of an amp.

current = charge/time

==> time = charge/current
 

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