Average force between an object and non-movable object?

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Homework Help Overview

The problem involves a golf ball of mass 41.8 g dropped from a height of 1.41 m onto a hard floor, where it bounces back to the same height. The objective is to determine the average force exerted on the ball during its contact with the floor over a duration of 0.012 s.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss how to calculate the change in velocity, with some expressing confusion about the initial and final velocities when the ball returns to the same height. There are questions regarding the calculation of velocities at ground level and the application of kinematic equations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the need to consider the velocities at ground level rather than at the heights. However, there is no explicit consensus on the method to calculate these velocities.

Contextual Notes

Participants are grappling with the implications of the ball returning to the same height and the assumptions regarding air resistance and friction. There is also a mention of the time duration of contact with the floor, which may influence the calculations.

sirfinklstin
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Homework Statement



A golf ball of mass 41.8 g is dropped from a height h = 1.41 m onto a hard floor and bounces back to exactly that same height. What is the average force (in N) on the ball during the 0.012 s that it was in contact with the floor?

Homework Equations



Impulse = Ft
Impulse = m(Vf - Vi)

The Attempt at a Solution


I am not quite sure how to proceed with this problem, because I am completely clueless as to how I should go about calculating the change in velocity, because if the ball returns to the same height, (no friction of air resistance) then arent the Vi and Vf both = 0?
 
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Hi sirfinklstin! :smile:
sirfinklstin said:
A golf ball of mass 41.8 g is dropped from a height h = 1.41 m onto a hard floor and bounces back to exactly that same height. What is the average force (in N) on the ball during the 0.012 s that it was in contact with the floor?

how I should go about calculating the change in velocity, because if the ball returns to the same height, (no friction of air resistance) then arent the Vi and Vf both = 0?

Yes, but you want the two velocities at ground level. :wink:
 
How would the velocities be calculated? 0 + (9.8 m/s)(1.41m)?
 
sirfinklstin said:
How would the velocities be calculated? 0 + (9.8 m/s)(1.41m)?

what? v = as ?? :confused:
 

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