- #1

agnimusayoti

- 240

- 23

- Homework Statement
- Using relative density data, estimate the average separation between molecules in hydrogen at STP (gas).

- Relevant Equations
- $$N (molecules) = n (mol) * N_A (molecules/mol)$$

The relative density data:

$${\rho_{H_{2},H_{2}O}}=\frac{\rho_{H_{2}}}{\rho_{H_{2}O}}=8.988\times10^{-5}$$

With avogadro number, thus I can obtain number of molecules per 1 ##m^3## of Hydrogen gas, that is:

$$N = \frac{{{\rho_{H_{2},H_{2}O}}}\times{\rho_{H_{2}O}}}{M_{r}}\times{N_{A}} $$

thus, I get

$$N = 2.685 \times 10^{25} \frac{molecules}{m^{3}}$$

The problem is I can't relate this result with the question which ask the average separation or average distance between the molecules.

Oh, btw, the solution mention 2 different geometries, that is ball and cubic.

Could you help me? Thanks guys!

$${\rho_{H_{2},H_{2}O}}=\frac{\rho_{H_{2}}}{\rho_{H_{2}O}}=8.988\times10^{-5}$$

With avogadro number, thus I can obtain number of molecules per 1 ##m^3## of Hydrogen gas, that is:

$$N = \frac{{{\rho_{H_{2},H_{2}O}}}\times{\rho_{H_{2}O}}}{M_{r}}\times{N_{A}} $$

thus, I get

$$N = 2.685 \times 10^{25} \frac{molecules}{m^{3}}$$

The problem is I can't relate this result with the question which ask the average separation or average distance between the molecules.

Oh, btw, the solution mention 2 different geometries, that is ball and cubic.

Could you help me? Thanks guys!