(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

You drive on Interstate 10 from San Antonio to Houston. Half thetimeat 55 km/h, and the other half at 90 km/h. On the way back, you travel half thedistanceat 55 km/h and the other half at 90km/h.

What is the average speed of the trip from San Antonio to Houston?

What is the average speed of the return trip from Houston to San Antonio?

What is the average speed of the whole trip?

3. The attempt at a solution

From San Antonio to Houston, half the time is traveled between the two speeds.

So:

d / (1/2)(d/55) + (1/2)(d/90)

68.27586 km/h average speed.

From Houston to San Antonio, half the distance is traveled at each speed.

((1/2)55t + (1/2)90t) / t

=(1/2)55 + (1/2)90

=

72.5 average speed.

My book seems to have the two answers reversed. Did I do these correctly?

**Physics Forums - The Fusion of Science and Community**

# Average speeds of back and forth trip

Have something to add?

- Similar discussions for: Average speeds of back and forth trip

Loading...

**Physics Forums - The Fusion of Science and Community**