Average speeds of back and forth trip

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Homework Help Overview

The problem involves calculating average speeds for a round trip between San Antonio and Houston, with specified speeds for different segments of the trip. The original poster presents calculations for average speeds based on time and distance, while questioning the correctness of their results in relation to a textbook reference.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculation of average speeds based on time and distance, with some focusing on the interpretation of "half the time" versus "half the distance." There are attempts to clarify the definitions and implications of these terms in the context of the problem.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem's wording. Some guidance has been offered regarding the distinction between time and distance in calculating average speed, but no consensus has been reached.

Contextual Notes

Participants are grappling with the implications of the problem's phrasing, particularly regarding the relationship between time spent at each speed and the distances traveled. There is a noted confusion about the correct application of these concepts to the average speed calculations.

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Homework Statement



You drive on Interstate 10 from San Antonio to Houston. Half the time at 55 km/h, and the other half at 90 km/h. On the way back, you travel half the distance at 55 km/h and the other half at 90km/h.

What is the average speed of the trip from San Antonio to Houston?
What is the average speed of the return trip from Houston to San Antonio?
What is the average speed of the whole trip?


The Attempt at a Solution



From San Antonio to Houston, half the time is traveled between the two speeds.

So:

d / (1/2)(d/55) + (1/2)(d/90)
68.27586 km/h average speed.

From Houston to San Antonio, half the distance is traveled at each speed.

((1/2)55t + (1/2)90t) / t
=(1/2)55 + (1/2)90
=
72.5 average speed.


My book seems to have the two answers reversed. Did I do these correctly?
 
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1MileCrash said:

Homework Statement



You drive on Interstate 10 from San Antonio to Houston. Half the time at 55 km/h, and the other half at 90 km/h. On the way back, you travel half the distance at 55 km/h and the other half at 90km/h.

What is the average speed of the trip from San Antonio to Houston?
What is the average speed of the return trip from Houston to San Antonio?
What is the average speed of the whole trip?

The Attempt at a Solution



From San Antonio to Houston, half the time is traveled between the two speeds.

So:

d / (1/2)(d/55) + (1/2)(d/90)
68.27586 km/h average speed.

From Houston to San Antonio, half the distance is traveled at each speed.

((1/2)55t + (1/2)90t) / t
=(1/2)55 + (1/2)90
=
72.5 average speed.My book seems to have the two answers reversed. Did I do these correctly?

You said, "From San Antonio to Houston, half the time is traveled between the two speeds."

I added the extra -- necessary -- parentheses in the following.
d / ((1/2)(d/55) + (1/2)(d/90))
What is (d/2)/55 ? ... It's the time required to travel a distance d/2 at a speed of 55...
etc ...

d/(total time) is average speed.

So this is not the case of: "half the time is traveled between the two speeds".
 
I am not sure what you are saying..

Does my work not agree with total distance / total time? Why are you telling me that?

Also, why isn't it a case of traveling half the time at each speed? That's explicitly what the problem says.
 
1MileCrash said:
...

Also, why isn't it a case of traveling half the time at each speed? That's explicitly what the problem says.

Because d/2 is half the distance !

So you are finding the time for half the distance at 55 + half the distance at 90.
 
Now I'm really confused. If time is (d/r), (1/2)(d/r) or (d/2r) is half of the time is it not??

Wait, I think I'm starting to get it. d/r is the time spent traveling d at r, so half of it is not half of the total time, only half of the time spent traveling d at r.

Thanks!
 
Last edited:

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