Average Velocity Graph: Determine its Values

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To determine the average velocity from the provided graph, the calculations for the specified time intervals are crucial. For the first interval (t = 25.0 s to t = 30.0 s), the displacement is likely 8 m, not 6 m, which affects the average velocity calculation. In the second interval (t = 35.0 s to t = 50.0 s), it's important to check the sign of the displacement, as it may impact the result. The initial calculations of 1 m/s and 2/3 m/s may be incorrect due to these factors. Accurate values are essential for correct submissions in online homework systems like Webassign.
Toxage
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Graph :

http://img354.imageshack.us/my.php?image=physicslp1.png

or

http://www.turboimagehost.com/p/766378/physics.JPG.html

Questions:

Determine its average velocity between the following times.

1. t = 25.0 s and t = 30.0s

2. t = 35.0 s and t = 50.0 s

The Attempt at a Solution



average velocity = overall displacement / overall time

1. 6m/5 sec = 1. m/s

2. 10 m / 15 s = 2/3 ms

My teacher uses on online homework program called Webassign, and both of these showed up as wrong. I don't know why. If anyone could help me that would be awesome.
 
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Toxage said:
Graph :

http://img354.imageshack.us/my.php?image=physicslp1.png

or

http://www.turboimagehost.com/p/766378/physics.JPG.html

Questions:

Determine its average velocity between the following times.

1. t = 25.0 s and t = 30.0s

2. t = 35.0 s and t = 50.0 s


The Attempt at a Solution



average velocity = overall displacement / overall time

1. 6m/5 sec = 1. m/s

2. 10 m / 15 s = 2/3 ms

My teacher uses on online homework program called Webassign, and both of these showed up as wrong. I don't know why. If anyone could help me that would be awesome.

On the first it looks like 8m not 6m. It will likely not think it's good if off by 10%.

Check your sign on the second one.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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