- #1

mrgenius24

**Alright, first I should probably let you all know that this is very simple physics, so I'm just looking for a quick answer.**

1. Homework Statement

1. Homework Statement

I'm trying to find a simple way to calculate the average velocity of an object where we know the average velocity during a number of segments of the distance traveled and we know that the segments of distance are all equal but we do not know the time elapsed. I would also like to know the opposite - what if we know of a couple of equal segments of time but we know nothing about the total distance traveled. I think that I know how to solve the latter, but I am not sure. I'll give you two examples so you know what I mean, in case that I was not clear enough:

1. A car traveled a certain distance during a certain amount of time. For 1/3 of the total distance, it traveled at 10 m/s. For the next 1/3, it traveled at 9 m/s, and for the final 1/3, it traveled at 15 m/s. What's the average velocity?

2. A car traveled a certain distance during a certain amount of time. For 1/3 of the total time, it traveled at 10 m/s. For the next 1/3, it traveled at 9 m/s, and for the final 1/3, it traveled at 15 m/s. What's the average velocity?

Also what happens if we have a problem like this:

3. A car traveled a certain distance during a certain amount of time. For 1/2 of the total distance, it traveled at 10 m/s. For 1/2 of the

__remaining__time, it traveled at 9 m/s, and for the next 1/2 of the remaining time it traveled at 15 m/s.

What formula do we use then?

## Homework Equations

Of course, I know of the formula which states that average velocity equals total distance traveled divided by the total time elapsed. I also think that I know that when we know that when the segments of time are equal, like in the example problem I gave above, we can just add together all the velocities and divide them by the total amount of time segments like this: (10 m/s + 9 m/s + 15 m/s)/3.

## The Attempt at a Solution

I know how to solve this problem the long way - I am just looking for the quick formula I was once told by a teacher but I can't remember it now.