Average Volume of Half a Sphere

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SUMMARY

The average volume of a half-submerged sphere can be calculated using the formula for the volume of a sphere, specifically 4/3 π r³. When submerged halfway, the volume of the submerged portion is 2/3 π r³. The discussion highlights an initial misconception of approximating the sphere as a cube, which is not necessary for accurate calculations. The final solution involves integration, although simpler methods may exist.

PREREQUISITES
  • Understanding of geometric volume formulas
  • Familiarity with integration techniques
  • Knowledge of spherical geometry
  • Basic principles of fluid mechanics
NEXT STEPS
  • Research the application of integration in calculating volumes of solids of revolution
  • Explore alternative methods for volume calculation of submerged objects
  • Study the principles of buoyancy and Archimedes' principle
  • Learn about the geometry of spheres and their properties
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Students in mathematics or physics, engineers dealing with fluid dynamics, and anyone interested in geometric volume calculations.

Icheb
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A sphere is submerged half way in water and pulled out at a constant speed. Now I have to find out the average volume of the part of the sphere that is under water.

The volume formula would be [tex]4/3 \pi r^3[/tex], now the part of the sphere that is under water at first would be [tex]2/3 \pi r^3[/tex].

Initially I thought I could assume the sphere to be a cube and then calculate the volume of the cube under water. Half of that volume would be the result then since the velocity is constant. However I'm not sure if that approximation is alright?


Edit: Never mind, found it! :)
 
Last edited:
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Glad you found it. Did you use integration to get the answer, or is there a simpler way?
 

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