'balanceable equations' (beginning chem)

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SUMMARY

The discussion focuses on balancing the chemical equation C3H5(NO3)3 → CO2 + N2 + H2O + O2. Participants clarify that the equation represents a decomposition reaction, not a single replacement reaction as initially thought. The key to balancing lies in creating an atom inventory for carbon (C), hydrogen (H), nitrogen (N), and oxygen (O) on both sides. It is emphasized that coefficients can be adjusted individually for each product rather than multiplying entire sides.

PREREQUISITES
  • Understanding of chemical reactions, specifically decomposition reactions.
  • Familiarity with balancing chemical equations.
  • Knowledge of stoichiometry and the concept of coefficients in chemical equations.
  • Ability to create an atom inventory for reactants and products.
NEXT STEPS
  • Practice balancing various types of chemical equations, focusing on decomposition reactions.
  • Study stoichiometry to understand the quantitative relationships in chemical reactions.
  • Learn about the Law of Conservation of Mass as it applies to chemical equations.
  • Explore tools or software for visualizing and balancing chemical equations.
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Chemistry students, educators, and anyone seeking to improve their skills in balancing chemical equations and understanding reaction types.

ncmm16
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Homework Statement


I've been balancing equations but this one has me really confused please help.
C3H5(NO3)3----> CO2 +N2 + H2O + O2


Homework Equations





The Attempt at a Solution


So I know that it is a single replacement reaction, (well I think so) but I don't know how to make the atom inventory because they aren't the same elements on both sides...so if you could please help me with that.
Then I can attempt to find the right coefficients on my own. :biggrin:
 
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ncmm16 said:
they aren't the same elements on both sides...so if you could please help me with that.

Erm, they are the same on both sides. You have C, H, N, and O on the left, and C, H, N, and O on the right.

Remember you can don't need to multiply entire sides by a number, you can just multiply each product individually, so you can have 3N2 on the right but 6 CO2 for example.
 
I would say it is decomposition.

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