Balancing a circle on a triangle?

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SUMMARY

The problem involves a hoop with mass m and radius R balanced on a knife blade, requiring the determination of the period of small oscillations. The moment of inertia of the hoop is given by I = mR², and the potential energy is expressed as U = mgRcos(θ). The professor advised using energy methods to analyze the system, leading to the conclusion that the oscillation behavior is dictated by the center of mass and the restoring force generated when the hoop is displaced. The final equation derived indicates that the system does not exhibit oscillatory motion, suggesting a misunderstanding of the setup and the forces involved.

PREREQUISITES
  • Understanding of moment of inertia, specifically for a hoop: I = mR²
  • Knowledge of potential energy in gravitational fields: U = mgh
  • Familiarity with kinetic energy in rotational motion: K = 1/2 I ω²
  • Basic principles of oscillatory motion and restoring forces
NEXT STEPS
  • Study the concept of restoring forces in oscillatory systems
  • Learn about the parallel axis theorem and its application in rotational dynamics
  • Explore energy conservation methods in mechanical systems
  • Investigate small angle approximations and their implications in physics problems
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Students studying classical mechanics, particularly those focusing on rotational dynamics and oscillatory motion, as well as educators seeking to clarify concepts related to energy methods in physics problems.

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Homework Statement



You're given a hoop with mass m and radius R balanced on top of a knife blade. (The diagram looks like a triangle with a circle balanced on the tip.) Find the period of small oscillations.

(Yes, that is all the problem says.)

Homework Equations



Moment of inertia of a hoop: I = mR2
U = mgh
K = 1/2 I w2 (writing omega as w)

The Attempt at a Solution



OK, here's the thing - I can't figure out how the hoop could be oscillating because I don't know what the restoring force is supposed to be. When questioned about it the professor said that has to do with the center of mass, but that we should use energy methods to solve the problem. So...

U = mgh (where h is the height of the center of mass)
h = R cos O (writing theta as O. theta is the angle the hoop rotates from the point of the triangle)
Then U = mgRcosO
K = 1/2 (Ihoop + mR2)w2 (by parallel axis theorem)
K = 1/2 2mRw2 = mRw2

E = K + U, dE/dt = 0

d/dt (MRw2 + mgRcosO ) = 0
2R d2O/dt2 - g O = 0 after small angle approximation and dividing through by m R w

The solution of that is just O(t) = c1 esqrt(g/2R)t + c2 e-sqrt(g/2R)t

That isn't oscillating. Of course that makes sense to me, because from what I understand there can be no restoring force...

What am I missing here?
 
Last edited:
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From your description I suspect you are not seeing the set up clearly.The blade is inside the hoop so that when at rest the centre of the hoop is vertically below the blade.when the hoop is displaced there will be a restoring force.
 

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