Balancing Chemical Equations Using Oxidation Numbers

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Discussion Overview

The discussion revolves around the process of balancing a chemical equation using oxidation numbers and various techniques for achieving balance. Participants explore different methods, including intuition, trial and error, and the half-reactions method, in the context of a specific homework problem.

Discussion Character

  • Homework-related
  • Technical explanation
  • Exploratory

Main Points Raised

  • One participant expresses confusion about balancing the equation, particularly regarding the number of iron atoms in the reactants and products.
  • Another participant suggests starting with 2Fe(OH)2 as a reagent to simplify the balancing process, emphasizing the importance of keeping iron atoms together.
  • A participant acknowledges the need to balance iron first and questions whether to rely on intuition and trial and error after reaching a certain point in the balancing process.
  • Another participant confirms that balancing by inspection is akin to using intuition and trial and error.
  • One participant mentions that the oxidation number method is not required but can be useful for complex equations.
  • A later reply proposes that the half-reactions method might be more effective by breaking the problem into simpler parts.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method for balancing the equation, with multiple approaches being discussed, including the oxidation number method and the half-reactions method. The discussion remains unresolved regarding the most effective technique.

Contextual Notes

Participants express uncertainty about the application of different balancing techniques and the effectiveness of each method in the context of the specific equation presented.

carlodelmundo
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Homework Statement



http://carlodm.com/pictures/problem.png

The Attempt at a Solution



I'm stuck. Usually I balance the equation by multiplying the Fe(OH)2 and Fe2O3 by 3. However, I can no longer do this because Fe2O3 has two iron's per one molecule.

Do I multiply one by 6 and the other by 3?
 
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Assume 2Fe(OH)2 is your reagent (why? because Fe2O3 contains two Fe atoms, just keep iron atoms forming one molecule of product togehter) - then you will have to multiply everything by 3. Basically that's the same as multiplitcation by 3 & 6, but it is easier to follow the reasoning.

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I see. So I should balance the reactant iron first, to 2... then do the multiplications of irons by 3.

I've arrived at that step but the products side still looks like a mess. Is this where I stop all "techniques" and rely on intution and trial and error to figure out the balanced equation?
 
Once you have Fe and Cr balanced rest you have to "balance by inspection" - which, as you have correctly pointed out, is a fancy name for "intuition and trial and error" :wink:

Do you have to use ON method?

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No we're not required to use the ON method... but it is a tool that we are able to utilize for ugly equations such as this. Thanks for your help! This'll come handy for reviewing my Chem exam.
 

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