Balancing equation for creation of Potassium benzoate

1. The problem statement, all variables and given/known data

Potassium benzoate C6H5CO2K can be prepared from benzyl alcohol, C6H5CH2OH, and potassium permanganate KMnO4 in aqueous KOH. The manganese is converted to MnO2

3. The attempt at a solution

So, my attempt to balance has left me scratching my head

C6H5CH2OH + KMnO4 [tex]\rightarrow[/tex] C6H5CO2K +MnO2

Question: Since it states aqueous KOH, where does that apply in balancing out this?

What would the equation be balanced?

Thanks in advance for your help.


KOH means you need to use OH- and water when balancing hydrogen and oxygen.

Do you know how to balance by half reactions? Can you split the system into reduction and oxidation half reactions?


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