Is This Reaction Between Calcium Chloride and Sodium Carbonate Balanced?

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Discussion Overview

The discussion centers around balancing the chemical reaction between aqueous calcium chloride and aqueous sodium carbonate, identifying the precipitate formed, and calculating the mass of that precipitate based on given quantities. The scope includes homework-related problem-solving and chemical reaction balancing.

Discussion Character

  • Homework-related
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant proposes the reaction: CaCl2(aq) + Na2CO3(aq) → CaCO3(aq) + 2NaCl(s) and questions if it is balanced.
  • Another participant confirms the reaction is balanced but suggests checking the solubility table for CaCO3 and NaCl to identify the correct precipitate.
  • A different participant presents the balanced reaction as CaCl2(aq) + Na2CO3(aq) → CaCO3(s) + 2NaCl(aq) and provides the net ionic equation as Ca2+(aq) + CO32-(aq) → CaCO3(s), noting it is balanced with the correct precipitate.
  • Another participant reminds to include charges in the net ionic equation and clarifies that the mass of Na2CO3 is not needed; instead, the focus should be on finding the mass of the precipitate from the given mass of calcium chloride.
  • This participant suggests starting with the 10.0 grams of calcium chloride to find moles, then moles of the precipitate, and finally grams of the precipitate.

Areas of Agreement / Disagreement

Participants generally agree that the reaction is balanced and that CaCO3 is the precipitate. However, there is some confusion regarding the calculation steps needed to find the mass of the precipitate, indicating that the discussion remains unresolved on that aspect.

Contextual Notes

There are limitations regarding the assumptions made about the solubility of the compounds involved and the specific steps required to calculate the mass of the precipitate, which have not been fully resolved in the discussion.

Valseki
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Homework Statement



Write and balance the reaction between aqueous calcium chloride and aqueous sodium carbonate. Write the net ionic reaction. If you start with 10.0g of calcium chloride and an excess of sodium carbonate, how many grams of precipitate will form?


Homework Equations





The Attempt at a Solution



CaCl_{2}_{(aq)} + Na_{2}CO_{3}_{(aq)} \rightarrow CaCO_{3}_{(aq)} + 2NaCl_{(s)}

This is what I get for a balanced reaction. From what I gather, this would be a double displacement and the sodium carbonate is precipitates out since carbonate has a low solubility. The other parts of this question I understand how to do as long as I am correct with this part. Is this reaction balanced or am I completely wrong? Thanks in advance!
 
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reaction is balanced but check your solubility table for CaCO3 and NaCl - what is the precipitate?
 
CaCl_{2}_{(aq)} + Na_{2}CO_{3}_{(aq)} \rightarrow CaCO_{3}_{(s)} + 2NaCl_{(aq)}

Is balanced with the correct precipitate.

The net ionic reaction is this:

Ca_{(aq)} + CO_{3}_{(aq)} \rightarrow CaCO_{3}_{(s)}

My problem is the next part, I can get the grams of the NaCO3 but I am confused on where to go from there.
 
first don't forget charges for Ca and CO3 in your net ionic equation

you also don't need gms of Na2CO3

You need to find the mass of the ppt which is the thing with (s)

start wi,th the 10.0 grms of the calcium chloride, find moles calcium chloride, find moles of the ppt, then find grams of the ppt.

how do you find moles from grams and grams from moles (MM = g/mol)
 

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