Ball bouncing on the floor - Normal reaction?

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SUMMARY

The discussion centers on the mechanics of a ball bouncing on the floor, specifically the relationship between normal force and weight. It is established that the normal force must be greater than the weight of the ball to produce a net upward acceleration, as dictated by Newton's second law of motion. Additionally, the normal force and weight are clarified as not being third-law pairs; rather, they act on different bodies. The conversation emphasizes the transformation of kinetic energy into strain energy and back during the bounce.

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sanado
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Hey guys,
Was just wondering if you could help me with what seems like a simple physics question.

When a ball bounces on the floor, is the normal force greater than that of the weight, resulting in the bloor bouncing upwards?

Or

Is it the case where the normal reaction force is the same as the weight and the only reason why the ball bounces back up is because the balls kinetic energy is transformed into strain energy which inturn is converted back into kinetic energy?

Or

Neither of the two
 
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sanado said:
Hey guys,
Was just wondering if you could help me with what seems like a simple physics question.

When a ball bounces on the floor, is the normal force greater than that of the weight, resulting in the bloor bouncing upwards?

Or

Is it the case where the normal reaction force is the same as the weight and the only reason why the ball bounces back up is because the balls kinetic energy is transformed into strain energy which inturn is converted back into kinetic energy?

Or

Neither of the two
All of the first and sort of part of the second. The normal force is greater than the weight (it has to be fore a net acceleration) because of conservation of energy.
 
"All of the first and sort of part of the second. The normal force is greater than the weight (it has to be fore a net acceleration) because of conservation of energy"

Well ifs that's the case, why is the normal force greater. Doesn't Newtons third law state that for every action there is an equal but opposite reaction? So wouldn't this mean that the acceleration would be equal to the normal force?
 
I think another reason is that action and reaction act on two different bodies. Ball exerts a force on the ground while ground in reaction,exerts a force on ball so it bounces up. They do not cancel each other's effect however they are equal in magnitude
 
sanado said:
Well ifs that's the case, why is the normal force greater. Doesn't Newtons third law state that for every action there is an equal but opposite reaction?
The normal force and the weight are not 3rd-law pairs. The pairs of forces that are equal and opposite per Newton's 3rd law are:
1) The Earth's force of gravity pulling the ball down (a.k.a., the weight) and the ball's force of gravity pulling the Earth up.
2) The contact force of the floor pushing up on the ball (the normal force on the ball) and the contact force of the ball pushing down on the floor.
So wouldn't this mean that the acceleration would be equal to the normal force?
The acceleration of the ball is determined by the net force on it via Newton's 2nd law. During its interaction with the floor, the net force is upwards (Net force = Normal - weight), so the acceleration is upwards.
 

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