Ball down hill w/ rotational motion

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SUMMARY

The discussion centers on determining the minimum coefficient of static friction required for a solid ball to roll down a hillside inclined at 69.0 degrees without slipping. The user initially approached the problem by treating the ball as a box and applying the equation F=ma, leading to the conclusion that the coefficient of static friction (μ_{s}) equals tan(69). However, this approach is incorrect as it fails to account for the rotational motion of the sphere. The correct analysis requires considering both translational and rotational dynamics, emphasizing the role of friction in enabling rolling motion.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of static friction and its coefficient
  • Knowledge of rotational dynamics and torque
  • Basic trigonometry, particularly sine and cosine functions
NEXT STEPS
  • Study the relationship between translational and rotational motion in rigid bodies
  • Learn how to apply the equations of motion for rolling objects
  • Explore the concept of torque and its calculation in rotational dynamics
  • Investigate the effects of different coefficients of friction on rolling motion
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to rolling motion and friction in rigid bodies.

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Homework Statement


A solid ball is released from rest and slides down a hillside that slopes downward at an angle 69.0 degrees from the horizontal.

What minimum value must the coefficient of static friction between the hill and ball surfaces have for no slipping to occur?

Homework Equations



The Attempt at a Solution


I'm not really sure what they mean here. If the ball is to roll down the hill, then it cannot "slide" at all, otherwise it would not roll. They don't give me any numbers to solve this with, and it's not a symbolic answer because the problem does not say "give your solution in terms of m,g,θ, et al.

What do they want me to do for this problem?

What I did was treat the ball as a box, and find the μ_{s} like so:

I said that parallel to, and down the hill was the increasing x axis. Then I summed up the forces, applied F=ma, so solve:

mgsin(69)-f_{s}=ma
f_{s} = μ_{s}N = μ_{s}(mgcos(69))
mgsin(69)-μ_{s}(mgcos(69)=ma
Because it's not slipping, acceleration is zero, thus ma = 0
mgsin(69)-μ_{s}(mgcos(69)=0
mgsin(69) =μ_{s}(mgcos(69)
μ_{s} = \frac{mgsin(69)}{mgcos(69)}
μ_{s} = tan(69)

Does that make sense?
 
Last edited:
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Apparently this is incorrect. How else can I tackle this problem? I don't understand why this won't work just as well as summing up the torque and setting them to zero.

Thanks.
 
Last edited:
You need to analyze both the rotational and the translational motion of the sphere. The friction affects both.

(Despite the sloppy wording of the problem statement, the sphere does not 'slide' down the hill. It rolls.)
 

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