Ball on String Elastic Collision

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Homework Help Overview

The problem involves two steel balls of different masses hanging from strings and colliding after being pulled to specific angles. The context includes concepts of conservation of energy and momentum in elastic collisions.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of conservation laws to find velocities before and after the collision. There are attempts to derive equations for the rebound angles based on energy conservation and momentum equations.

Discussion Status

Some participants are actively working through the equations and seeking clarification on their approaches. There is a focus on deriving the correct expressions for velocities after the collision, with some guidance offered on the relationships between the variables involved.

Contextual Notes

Participants express uncertainty about their calculations and the correctness of their derived formulas. There is a sense of urgency due to a deadline for submission.

jzwiep
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Homework Statement



A 250 g steel ball and a 500 g steel ball each hang from 3.5-m-long strings. At rest, the balls hang side by side, barely touching. The 250 g ball is pulled to the left until the angle between its string and vertical is 22 degrees The 500 g ball is pulled to a 22 degree angle on the right. The balls are released so as to collide at the very bottom of their swings.

What angle does each ball rebound?

Homework Equations



Conservation of Energy
U = K' ----> K = U'
Conservation of Momentum (at collision)
p1 + p2 = p1' +p2'

h=L(1-cos(22))

The Attempt at a Solution



I found the v for both immediately before the collision by:

U=K'
v=sqrt(2g(L-Lcos(22))

Then used that value to find v1 and v2 after the collision with:

-v=2v2' - v1'

and

3v2=v1'2 + 2v2'2

and got two quadratics:

v2
and
v1

I plugged those v values back into the K = U' formula and got:

Theta 1: 14.6636
Theta 2: 8.45

Where did I go wrong?
 
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Show the equations you solved.
 
For substitution into the second double variable formula:

v2'=(-v+v1')/2

v1'=(2v2'-v)

For turning the v' values back into angles:

h=v2/2g

theta=arccos((l-h)/l) (where l is the length of string)

Anything else? I'm not really sure which equations you meant.
 
Anyone? I tried working through it again, and ended up with the same wrong answer. It's due tonight. :(
 
What did you get for v1' and v2' in terms of v?

ehild
 
jzwiep said:
Then used that value to find v1 and v2 after the collision with:

-v=2v2' - v1'

-v=2v2' + v1'

What do you get for v1' and v2' in terms of v?

ehild
 
Last edited:
ehild said:
-v=2v2' + v1'

What do you get for v1' and v2' in terms of v?

ehild

Thanks, that did it. Just out of curiosity, where did I go wrong deriving the original formula?

mv -2mv = 2mv2' - mv1'
-mv=m(2v2' - v1')
-v=2v2' - v1'

Mass 1 is going in the positive direction first, then negative. Mass 2 is vice-versa.
 
I see, you used the speeds instead of velocities. Go ahead. What are the final results for v1' and v2'?

ehild
 

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