Ball throws upward, find maximum height

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SUMMARY

The discussion focuses on calculating the maximum height of a ball thrown upward with an initial velocity of 10 m/s, while neglecting friction. The key conclusion is that the maximum height can be determined using the kinematic equation for motion under constant acceleration, specifically by recognizing that the final velocity at the peak height is zero. The mass of the ball is irrelevant in this calculation as the gravitational force acts uniformly on all objects regardless of mass.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of gravitational acceleration (approximately 9.81 m/s²)
  • Familiarity with concepts of kinetic and potential energy
  • Basic algebra for solving equations
NEXT STEPS
  • Study the kinematic equation: \(d = \frac{v_i^2}{2g}\) for maximum height calculations
  • Learn about energy conservation principles in physics
  • Explore the effects of air resistance on projectile motion
  • Investigate the relationship between initial velocity and maximum height in projectile motion
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding projectile motion and energy transformations.

Amber3046
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Homework Statement


You throw a ball directly upward giving the ball an initial velocity of 10m/s. Neglecting friction, what would be the maximum height of the ball? (Explain why you do not need to know the mass of the ball)


Homework Equations


not sure


The Attempt at a Solution


vi=10m/s d=?
not much of an attempt, i know
 
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The ball has an initial kinetic energy, which is transformed into an increase in gravitational potential energy.

Max height occurs when vy equals zero.
 
Last edited by a moderator:
so if v1 = 10 m/s , think wut would the speed be at maximum height , and remember there is always the acceleration of gravity [ down ] acting on all object thrown upward!
 
Last edited:

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