Balmer, Lyman, and Paschen series

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Homework Statement



4. (a) Find the shortest wavelength photon emitted by a downward electron transition in the
Lyman, Balmer, and Paschen series of the hydrogen atom.

My only question is, what energy state is the electron starting from? is it n=infinity? or is there some part of this I am missing?
 
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Electrons can start from any energy level and end up in any energy level. Which transition would give the greatest frequency?
 
well the higher the starting energy level, the shorter the wavelength, so i would assume n=infinity,

so what's n=infinity for hydrogen?
 
I have the same problem, I need to find "E-max" for hydrogen. I know that I should take ((2.18*10^-18)/(6.63*10^-34)) * ((1/n)-(1/m)) (Where n>m)