Bar forces (1-6) should be calculated?

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Homework Help Overview

The discussion revolves around calculating the forces in a symmetrical framework, with specific attention to the effects of a movable bearing on the left side. Participants are attempting to clarify their understanding of the problem setup and the application of equilibrium equations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are discussing the direction of forces acting on the framework and whether to assume a direction for calculations. There are attempts to clarify the setup and the implications of the movable bearing. Some participants express uncertainty about their calculations and seek guidance on how to proceed.

Discussion Status

Some participants have provided feedback on the original poster's diagram and attempts, emphasizing the need to show a clear attempt at a solution. There is ongoing exploration of the problem, with various interpretations and suggestions being discussed without a definitive consensus on the correct approach.

Contextual Notes

Participants mention specific values for forces and dimensions, indicating that certain parameters are given, but there is uncertainty regarding their application in the calculations. The discussion also reflects the constraints of forum rules requiring attempts at solutions before receiving further assistance.

Dan123
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Homework Statement


The pictue shows a symmetrical framework. I should calculate the bar forces. and make a "Clear Cut".I*m not shure because of the left movable bearing (on the left side)!?

1.jpg


Homework Equations


total x=0
total y=0
total M=0

The Attempt at a Solution


Here is my "Clear Cut" is it correctly?

2.jpg
 

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You are right that the force at lower left acts at 45 degrees, but do you think it acts up or down on the frame?
 
haruspex said:
You are right that the force at lower left acts at 45 degrees, but do you think it acts up or down on the frame?

I'm not shure, but our professor said, we should just set it in one direction, and after we calculate it we can see which the right direction was (if it is negative, we have to switch the direction).

But do you know, how I can solve this ...? I'm not shure
 
Dan123 said:

Homework Statement


The pictue shows a symmetrical framework. I should calculate the bar forces. and make a "Clear Cut".I*m not shure because of the left movable bearing (on the left side)!?

View attachment 218785

Homework Equations


total x=0
total y=0
total M=0

The Attempt at a Solution


Here is my "Clear Cut" is it correctly?

View attachment 218786
i forgot...there is given

F, h, F1=2F and F2=3F
 
Dan123 said:
our professor said, we should just set it in one direction, and after we calculate it we can see which the right direction was (if it is negative, we have to switch the direction).
That's correct, but it seemed you were asking for comments on your diagram.
Dan123 said:
how I can solve this
That's not what you asked originally. As per forum rules you need to show an attempt at a solution. Apply the relevant equations you quoted.
 
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haruspex said:
That's correct, but it seemed you were asking for comments on your diagram.

That's not what you asked originally. As per forum rules you need to show an attempt at a solution. Apply the relevant equations you quoted.
ok, I will send my solution...or my try :)
 
haruspex said:
That's correct, but it seemed you were asking for comments on your diagram.

That's not what you asked originally. As per forum rules you need to show an attempt at a solution. Apply the relevant equations you quoted.
So here is my try...I can't finish it...I don't get the right answer (the right answer is: S1=6F ; S2=(√5)/2 F ; S3=1,5F ; S4=7F ; S5=(√5)/2 F ; S6=1,5F )

IMG_20180123_203046_376.jpg


IMG_20180123_203116_656.jpg


I thought of dividing it in two parts (special calculation method...?!

Could you pplease help me :)
 

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Dan123 said:
(the right answer is: S1=6F ; S2=(√5)/2 F ; S3=1,5F )
Doesn't look right to me.
I was suspicious that you may have specified the wrong values for the applied forces, so I made them arbitrary.
Consider the leftmost triangle and take moments about its lower right corner. Let N be the normal force from the lower left support, Gt the downward load at the top of the triangle, and Gr the load at the bottom right.
Take members 1 and 2 to be under compression, 3 under tension.
Y: N/√2-2S2/√5=Gr+Gt
X: N/√2=S2/√5-S3+S1
M: N/√2=Gt/2+S1
If I substitute the answers in the X and M equations I get N=5F√2, Gt=-F.
 
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